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Svet_ta [14]
3 years ago
8

A chemist has two large containers of sulfuric acid solution, with different concentrations of acid in each container. Blending

310 mL of the first solution and 590 mL of the second gives a mixture that is 11.58% acid, whereas blending 85 mL of the first mixed with 490 mL of the second gives a 7.25% acid mixture. What are the concentrations of sulfuric acid in the original containers?
Chemistry
1 answer:
vitfil [10]3 years ago
6 0

Answer:

0.015% and 0.012%

Explanation:

using simultaneous equation

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An alloy is a mixture that has
defon

Answer:

an alloy is a mixture of elements that has metallic properties

Explanation:

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3 years ago
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How many grams of carbon are present in 45.0 g of CCl4?
lisabon 2012 [21]
To determine the amount of a certain element in a compound, we use the ratio of the elements from the compound. We calculate is follows:

45.0 g CCl4 ( 1 mol CCl4 / 153.82 g CCl4 ) ( 1 mol C / 1 mol CCl4 ) ( 12.01 g C / 1 mol C ) = 3.5135 g carbon present

Hope this answers the question. Have a nice day.
5 0
3 years ago
Organisms can either be made of one cell or made of more than one cell
Alika [10]

Answer:

The statement is true.

Explanation:

Organisms can be unicellular (made up of one cell) or multicellular (consisting of more than one cell).

I hope this helps in any way :)

4 0
3 years ago
Temperature in degrees Fahrenheit can be converted to Celsius by first subtracting 32, then dividing by 1.8. What is the Celsius
kap26 [50]

Answer:

31.1°C

Explanation:

Given parameters:

  Temperature = 88°F

The formula of the to convert is:

         T°F = T°C - 32  / 1.8  = \frac{TC - 32}{1.8}

Now input the parameters and solve;

       T°F =\frac{ 88  -32}{1.8}

      T°F = 31.1°C

7 0
2 years ago
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What is the molarity of NaOH if 83.5 mL of NaOH is needed to react with 35.0mL of a 0.275 M solution of H2SO4?
Lostsunrise [7]

Answer:

0.231 mol/L

Explanation:

The first step is to write the balanced equation for this reaction:

H_{2}SO_{4} +2NaOH ===> Na_{2}SO_{4}  +2H_{2}O

The second step is to find the number of moles in the acid:

number of moles = volume * concentration

                             = 0.035 L * 0.275 mol/L

                             = 0.009625 mol

The third step is to use the molar ratio from the balanced chemical equation to find the number of moles of NaOH that can neutralize 0.009625 mol of sulphuric acid.

n(sulphuric acid) : n(sodium hydroxide)

          1                :                   2

0.009625 mol    :                   x

x =  0.01925 mol

Fourth step is to calculate the concentration of sodium hydroxide:

concentration = \frac{number of moles}{volume} = \frac{0.01925}{0.0835} =0.231 mol/L

7 0
3 years ago
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