Which operations are defined for any two real numbers?

Mathematics

2 answers:

ioda3 years ago

6 0

The appropriate choices are

... addition

... subtraction

.... multiplication

_____

Division by zero is not defined.

Igoryamba3 years ago

4 0

Answer:

Addition, Subtraction and Multiplication is defined for every real number.

Step-by-step explanation:

Given : any two real numbers.

We have to choose from the given options that defines operation for any two real numbers.

Since, Addition, Subtraction and Multiplication is defined for every real number (including 0 )

1) Addition

2+ 0 = 2 ( 2 belong to real number)

2) Subtraction

5 - 0 = 5 ( 5 belong to real number)

3) Multiplication

7 × 0 = 0 ( 0 belong to real number)

4) But for division

$\frac{3}{0}$ is not defined

Thus, Addition, Subtraction and Multiplication is defined for every real number.

You might be interested in

One container of yogurt is $0.79 at the grocery store. Nicola has a coupon for 30% off her entire purchase. She has $10.00 to sp

AVprozaik [17]

30 percent off means that we can just reduce 30 percent from .79 to get .55.
divide 10.00 by .55 to get the answer of 18.18. The max yogurts Nicola can buy is 18.

7 0

4 years ago

What time did Katie start practicing if ate snack for 15min, watched tv for 30 min and practiced for 45 minutes

VMariaS [17]

If she ended at 6 pm.

practiced for 45 minutes. 6 pm work back 45 minutes, she started practicing at 5:15pm.

watched tv for 30 minutes. 5:15 pm work back 30 minutes, she started watching tv at 4:45 pm

ate snack for 15 minutes. 4:45 pm work back 15 minutes, she started eating her snacks at 4:30 pm.

8 0

3 years ago

Using quadratic equation: help me solve it <img src="https://tex.z-dn.net/?f=10x%20-%20%20%5Cfrac%7B1%7D%7Bx%20%7D%20%20%3

pochemuha

Answer:

$10x - \frac{1}{x} = 3 \\ 10x = 3 + \frac{1}{x} \\ 10x = \frac{3x + 1}{x} \\ 10x \times x = 3x + 1 \\ 10 {x}^{2} = 3x + 1 \\ 10 {x}^{2} - 3x - 1 = 0 \\ 10 {x}^{2} - 5x + 2x - 1 = 0 \\ 5x(2x - 1) + 1(2x - 1) = 0 \\ (5x + 1)(2x - 1) = 0 \\ \\ 5x + 1 = 0 \\ 5x = - 1 \\ x = \frac{ - 1}{5} \\ \\ 2x - 1 = 0 \\ 2x = 1 \\ x = \frac{1}{2}$