How do i determine the domain and the equation of the vertical asymptote of the equation f(x)=ln (x+2)-1?
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Answer:
The parabola is translated down 2 units.
Step-by-step explanation:
You have the parabola f(x) = 2x² – 5x + 3
To change this parabola to f(x) = 2x² - 5x + 1, you must have performed the following calculation:
f(x) = 2x² – 5x + 3 -2= 2x² - 5x + 1 <u><em>Expresion A</em></u>
The algebraic expression of the parabola that results from translating the parabola f (x) = ax² horizontally and vertically is g (x) = a(x - p)² + q, translating in the same way as the function.
- If p> 0 and q> 0, the parabola shifts p units to the right and q units up.
- If p> 0 and q <0, the parabola shifts p units to the right and q units down.
- If p <0 and q> 0, the parabola shifts p units to the left and q units up.
- If p <0 and q <0, the parabola shifts p units to the left and q units down.
In the expression A it can be observed then that q = -2 and is less than 0. So the displacement is down 2 units.
This can also be seen graphically, in the attached image, where the red parabola corresponds to the function f(x) = 2x² – 5x + 3 and the blue one to the parabola f(x) = 2x² – 5x + 1.
In conclusion, <u><em>the parabola is translated down 2 units.</em></u>
