3 years ago

How do i determine the domain and the equation of the vertical asymptote of the equation f(x)=ln (x+2)-1?

Mathematics

1 answer:

svetlana [45]3 years ago

3 0

If I am reading the equation correctly, I do not believe it has a solution.

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Help asap please!!..

Semenov [28]

Answer:

9x² - 4/3x + ¼

Step-by-step explanation:

(3x - ½)²

(3x - ½)(3x -½)

9x² - ⅔x - ⅔x + ¼

9x² - 4/3x + ¼

5 0

2 years ago

Help pls i’m too dumb to know what I’m doing right now

Finger [1]

20+2x6

I don’t know. I just hope I’m helpful

6 0

2 years ago

2 (Picture) CONVERGENT AND DIVERGENT SERIES PLEASE HELP!!

Ivanshal [37]

Answer:

This series is divergent

Step-by-step explanation:

we are given a series

Firstly, we will find nth term

Numerator:

3, 4, 5,...

so, nth term will be

$a_n=n+3$

Denominator:

4,5,6,....

so, nth term will be

$b_n=n+4$

so, we can find it's nth term as

$c_n=\frac{n+3}{n+4}$

we can use divergent test

$\lim_{n \to \infty} c_n=\lim_{n \to \infty} \frac{n+3}{n+4}$

we can divide top and bottom by n

$\lim_{n \to \infty} c_n= \lim_{n \to \infty} \frac{n/n+3/n}{n/n+4/n}$

$\lim_{n \to \infty} c_n= \lim_{n \to \infty} \frac{1+3/n}{1+4/n}$

now, we can plug n=inf

$\lim_{n \to \infty} c_n= \frac{1+0}{1+0}$

$\lim_{n \to \infty} c_n=1$

Since, it is non-zero value

so, this series is divergent

8 0

3 years ago

Can someone please help me with this question?

amid [387]

Answer:

Answer: Function A is represented by the quadrant

Step-by-step explanation:

4 0

2 years ago

What is the height of an equilateral triangle with all sides equal to 8

vitfil [10]

an equilateral triangle has a square root height if 3 so I'm guessing if you multiply square root of 3 times 8

3 0

3 years ago

Read 2 more answers