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kramer
3 years ago
11

How many ms are in 12.00 ks?

Physics
2 answers:
Murrr4er [49]3 years ago
7 0
It is 12000000 ms in 12.00 ks!
Mrrafil [7]3 years ago
6 0

"Kilo" is 3 orders of magnitude larger than the base unit, while "milli" is 3 orders of magnitude smaller. That is, 1 second is 10^{-3} kiloseconds and 10^3 milliseconds. This means 1 ks is 10^6 ms, so

12.00\,\mathrm{ks}\cdot\dfrac{10^6\,\mathrm{ms}}{1\,\mathrm{ks}}=12.00\times10^6\,\mathrm{ms}

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4 0
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A 1500 kg weather rocket accelerates upward at 10.0 m/s . It explodes 2.00 s after liftoff and breaks into two fragments, one tw
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20 m/s is the speed of the heavier fragment just after the explosion.

Newton's second law of motion states that the resultant force applied to an object is directly proportional to the mass and acceleration of the object.

F = ma                   where, F = Force (Newton)

                                          m= mass

                                          a = acceleration

Given:

mass of rocket = M = 1500 kg

acceleration of rocket = a = 10 m/s²

elapsed time = t = 2.00 s

mass of lighter fragment = m₁ = m = 500 kg

mass of heavier fragment = m₂ = 2m = 1000 kg

maximum height of lighter fragment = h = 530 m

Let's calculate the final speed of the rocket just before the explosion:

v = u + at

v = 0 + 10(2)

v = 20 m/s

Then, we will calculate the height of the rocket just before the explosion:

h' = ut + \frac{1}{2}at^{2}

h' = 0 + \frac{1}{2} (10)(2.00)^{2}

h' =20m

The initial speed of lighter fragment just after the explosion:

v^{2}₁ = u^{2}₁ - 2gΔh

v^{2}₁ = u^{2}₁ - 2g (h - h')

0^{2} = u^{2}₁- 2(9.8) (530-20)

u^{2}₁=9996

u₁ =\sqrt{9996}  m/s

Using Conservation of Momentum Law :

M v=m₁ u₁ +  m₂u₂

1500 (20)= 500(\sqrt{9996} ) + 1000u₂

u₂ ≅ - 20 m/s

Learn more about Newton's law of motion here:

brainly.com/question/10454047

#SPJ4

7 0
2 years ago
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