Answer:
The liquid is vaprizing at point C
This question is incomplete, the complete question is;
A football quarterback throws a 0.408 kg football for a long pass. While in the motion of throwing, the quarterback moves the ball 1.909 m, starting from rest, and completes the motion in 0.439 s. Assuming the acceleration is constant, what force does the quarterback apply to the ball during the pass
;
a) F_throw = 8.083 N
b) F_throw = 9.181 N
c) F_throw = 2.284 N
d) F_throw = 16.014 N
e) None of these is correct
Answer:
the quarterback applied a force of 8.083 N to the ball during the pass
so Option a) F_throw = 8.083 N is the correct answer
Explanation:
Given that;
m = 0.408 kg
d = 1.909 m
u = 0 { from rest}
t = 0.439 s
Now using Kinetic equation
d = ut + 1/2 at²
we substitute
1.909 = (0 × 0.439) + 1/2 a(0.439)²
1.909 = 0 + 0.09636a
1.909 = 0.09636a
a = 1.909 / 0.09636
a = 19.8111 m/s²
Now force applied will be;
F = ma
we substitute
F = 0.408 × 19.8111
F = 8.0828 ≈ 8.083 N
Therefore the quarterback applied a force of 8.083 N to the ball during the pass
so Option a) F_throw = 8.083 N is the correct answer
Answer:
25N
Explanation:
Assuming the lab is on earth:
w = mg = 2.5 (9.81) = 25N
A. is a neutral substance.
Only neutral substances (like pure water) can have a pH of 7.
Answer:
962 rpm.
Explanation:
given,
angular acceleration = 190 rad/s²
initial angular speed = 0 rad/s
final angular speed = 7200 rpm
=
=
we need to calculate the revolution of disk after 10 s.
time taken to reach the final angular velocity
using equation of angular motion


t = 4 s
rotation of wheel in 4 s



θ = 1520 rad


now, revolution of the disk in next 6 s
angular velocity is constant


θ_f = 6044 rad
θ_f = 
revolution of the computer hard disk
θ_f = 962 rpm.
total revolution of the computer disk after 10 s is equal to 962 rpm.