Answer:
4000J
Explanation:
Given parameters:
Weight of the man = 800N
Height of ladder = 5m
Unknown:
Gravitational potential energy gained = ?
Solution:
The gravitational potential energy is due to the position of a body.
Gravitational potential energy = weight x height
Now insert the parameters;
Gravitational potential energy = 800 x 5 = 4000J
Answer:
0.04225 Nm
Explanation:
N = Force applied = 5 N
= Coefficient of static friction = 0.65
d = Diameter of knob = 1.3 cm
r = Radius of knob =
Force is given by
When we multiply force and radius we get torque
Torque on thumb
Torque on forefinger
The total torque is given by
The most torque that exerted on the knob is 0.04225 Nm
In order to determine this, we will first need some conversions. We will need to convert metric tons and grams into one another and also cubic centimeters to cubic meters into one another.
1 metric ton = 1000 kg
1 kg = 1000 grams
1 metric ton = 10⁶ grams
So 10⁶ grams / metric ton
1 meter = 100 cm
1 m³ = (100)³ cm³
1 m³ = 10⁶ cm³
So 10⁶ cm⁶ / m³
Now, we manipulate the given value:
(19.3 grams / cm³) * (1 metric ton / 10⁶ grams) * (10⁶ cm³ / m³)
= 19.3 metric tons / m³
The density of gold is 19.3 metric tons meter meter cubed.
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The answer is 21m because the motion is in one dimension with constant acceleration.
The initial velocity is 0, because it started from rest, the acceleration <span>ax</span> is <span>4.7<span>m<span>s2</span></span></span>, and the time t is <span>3.0s</span>
Plugging in our known values, we have
<span>Δx=<span>(0)</span><span>(3.0s)</span>+<span>12</span><span>(4.7<span>m<span>s2</span></span>)</span><span><span>(3.0s)</span>2</span>=<span>21<span>m</span></span></span>