The denominator is 4 and the numerioar to make factor 1/2 would be 4/8 then 1/2
Answer:
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>>In Fig. 6.43, if PQ PS, PQ∥ SR, SQR = 2
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In Fig. 6.43, if PQ⊥PS,PQ∥SR,∠SQR=28
0
and ∠QRT=65
0
, then find the values of x and y.
463685
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Solution
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Given, PQ⊥PS,PQ∥SR,∠SQR=28
∘
,∠QRT=65
∘
According to the question,
x+∠SQR=∠QRT (Alternate angles as QR is transversal.)
⇒x+28
∘
=65
∘
⇒x=37
∘
Also ∠QSR=x
⇒∠QSR=37
∘
Also ∠QRS+∠QRT=180
∘
(Linear pair)
⇒∠QRS+65
∘
=180
∘
⇒∠QRS=115
∘
Now, ∠P+∠Q+∠R+∠S=360
∘
(Sum of the angles in a quadrilateral.)
⇒90
∘
+65
∘
+115
∘
+∠S=360
∘
⇒270
∘
+y+∠QSR=360
∘
⇒270
∘
+y+37
∘
=360
∘
⇒307
∘
+y=360
∘
⇒y=53
∘
Step-by-step explanation:
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Answer:
add up the exponents on each prime number
Step-by-step explanation:
2^2= 2x2
3^2=3x3
so 36=2^2x3^2=2x2x3x3
I’ll try to make a step by step demonstration! Feel free to skip to step 5 for the answer, though
1. The formula for a right triangular prism is (1/2)*base*height*length, and we know what the base (4 cm) and length (8 cm) are, but not the height
2. To find the height we must divide the side triangle into two, which then gives us two right triangles
3. Focusing on just one of the right triangles, its base will be 2 cm rather than 4 (as it has been divided by two) and its hypotenuse will be 4 cm; using Pythagorean’s theorem (a^2 + b^2 = c^2), solve for the missing side (the height), which should end up being √12
4. Multiply! (1/2)4*√12*8 ≈ 55.425
5. Round to the nearest tenth —> 55.4
I hope this helped somewhat! Comment if clarification is needed
