X = number of correct answers
Y = number of incorrect answers
School A has 174 points and school B has 102 points.
A = 174
B = 102
School A has the same number of correct and incorrect answers during the final round.
A = 174 + 10X - 6Y
School B gives no incorrect answers and the same number of correct answers as school A.
B = 102 + 10X
The contest ends with the two schools tied.
Score = 174 + 10X - 6Y = 102 + 10X
174 + 10X - 6Y = 102 + 10X
The general form for a line through two points (a,b) and (c,d) is
(c-a)(y-b)=(d-b)(x-a)
This is better than the slope forms because it works in the no slope case, as does the standard form.
If you haven't seen it before, it works because when (x,y)=(a,b) we get (c-a)(b-b)=(d-b)(a-a), both sides zero, and when (x,y)=(c,d) we get (c-a)(d-b)=(d-b)(c-a), clearly equal sides.
Here we have
(0 - -5)(y - 0) = (-9 - 0)(x - - 5)
5y = -9(x+5)
5y = -9x - 45
9x + 5y = -45
Ironically there are two standards for standard form; one with the constant alone on the right and one with the whole thing equal to zero. I like the constant alone.
Answer: 9x + 5y = -45
Check:
We check each point is on the line
(-5,0)
9(-5) + 5(0) = -45, good
(0, -9)
9(0) + 5(-9) = -45, good again
Answer:
Liam has 3 whole pizza along with 1/3 of a pizza.
In decimal, Liam has 3.33 of Pizza.
Step-by-step explanation:
Given
Quantity of pizza with Martin = 5/6 of a pizza
Pizza with Liam = 4*Quantity of pizza with Martin
Pizza with Liam = 4*5/6 of a pizza
Pizza with Liam = 10/3 of a pizza = 3 1/3 of pizza.
Thus, Liam has 3 whole pizza along with 1/3 of a pizza.
In decimal Liam has 3.33 of Pizza.
Answer:
i cant see the question
Step-by-step explanation:
Answer:

Step-by-step explanation:


