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3 years ago

-4/3x-6=-26 A. -27B. -15C. 15D. 27

Mathematics

1 answer:

JulsSmile [24]3 years ago

5 0

Answer:

C. 15

Step-by-step explanation:

-4/3x-6=-26

The first step is to add 6 to each side

-4/3x-6+6=-26+6

-4/3x =-20

Now multiply by -3/4 to isolate x.

-3/4 * -4/3x = -3/4 * -20

x = 60/4

x = 15

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Answer:

Step-by-step explanation:

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The approximate total mass is the number of atoms multiplied by the weight of an atom.

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Speed is the ratio of distance and time. When we divide f(x) by g(x) we will get the speed of the flock that is 9 miles/hour.

<h3>What is speed?</h3>

Speed can be defined as the rate of change in the position of an object. It is given as,

$Speed = \dfrac{Distance}{Time}$

Given to us

Distance traveled, f(x) = 2x+26

Time, g(x) = x − 1

As we know that the ratio of distance and time is equal to the speed of the object. Since the distance traveled by the flock of birds is given also, the time needed for them to travel the distance is also given.

We need to find f divided by g of 5, which is the speed of the flock,

$Speed = \dfrac{Distance}{Time} = \dfrac{f(x)}{g(x)}$

$Speed = \dfrac{f(x)}{g(x)} = \dfrac{2x +26}{x-1}$

$Speed = \dfrac{f(5)}{g(5)} = \dfrac{2(5) +26}{(5)-1}\\\\Speed = 9 \rm\ miles/ hour$

Hence, when we divide f(x) by g(x) we will get the speed of the flock that is 9 miles/hour.

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Suppose you have two urns with poker chips in them. Urn I contains two red chips and four white chips. Urn II contains three red

Neporo4naja [7]

Answer:

Multiple answers

Step-by-step explanation:

The original urns have:

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Urn 2 = 3 red + 1 white = 4 chips

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The probability of take a red one is : $\frac{1}{3}$ (2 red from 6 chips(2/6=1/2))

For a white one is: $\frac{2}{3}$ (4 white from 6 chips(4/6=(2/3))

Then we put this chip into the second urn:

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First if the chip we got from the first urn was white. The urn 2 now has 3 red + 2 whites = 5 chips
Second if the chip we got from the first urn was red. The urn two now has 4 red + 1 white = 5 chips

If we select a chip from the urn two:

In the first case the probability of taking a white one is of: $\frac{2}{5}$ = 40% ( 2 whites of 5 chips)
In the second case the probability of taking a white one is of: $\frac{1}{5}$ = 20% ( 1 whites of 5 chips)

This problem is a dependent event because the final result depends of the first chip we got from the urn 1.

For the fist case we multiply :

$\frac{4}{6}$ x $\frac{2}{5}$ = $\frac{4}{15}$ = 26.66% ( $\frac{4}{6}$ the probability of taking a white chip from the urn 1, $\frac{2}{5}$ the probability of taking a white chip from urn two)

For the second case we multiply:

$\frac{1}{3}$ x $\frac{1}{5}$ = $\frac{1}{30}$ = .06% ( $\frac{1}{3}$ the probability of taking a red chip from the urn 1, $\frac{1}{5}$ the probability of taking a white chip from the urn two)

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