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3 years ago

14

If (f + g)(x) = 3x2 + 2x – 1 and g(x) = 2x – 2, what is f(x)

1 answer:

Flauer [41]3 years ago

5 0

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In ΔNOP, the measure of ∠P=90°, the measure of ∠N=59°, and PN = 7.4 feet. Find the length of OP to the nearest tenth of a foot.

lina2011 [118]

Answer:

12.3 feet.

Step-by-step explanation:

As we are given that $\triangle NOP$ is an right angled triangle.

$\angle P = 90 ^\circ \\\angle N = 59 ^\circ\\Side\ PN = 7.4 \text{ feet}$

And we have to find out the value of side OP to the nearest tenth of a foot by rounding off the value as seen in the attached figure as well.

By using Trigonometric functions in a right angled $\triangle$ , we know that:

$tan \theta = \frac{Perpendicular}{Base}$

Here, $\theta$ is $\angle N$ , Perpendicular is side <em>OP</em> and Base is side <em>PN</em>.

So, $tan 59^\circ = \frac{OP}{PN}$

$\Rightarrow OP = PN \times tan59^\circ$

Putting the values of <em>PN </em>and $tan59^\circ$ .

$OP = 1.66 \times 7.4\\\Rightarrow OP = 12.3 ft$

Hence, the value of <em>OP </em>is $12.3\ feet$ .

8 0

3 years ago

Sarah uses a total of 36 sheets of paper for her story. Each chapter is 9 pages , how many pages are in her short story

MariettaO [177]

Answer:

4 pages

Step-by-step explanation:

You divide 36 by 9

4 0

2 years ago

Area of a lake is 9/20 a square mile. The width is 1/5 the length. What is the length and the width.

katovenus [111]

Say, length =x mileWidth =. x/5 milex*x/5=9/2020x*x=45x*x=45/20 =9/4x=3/2 mileLength =3/2 milesWidth=. 3/10 miles

3 0

3 years ago

Find the missing geometric means in this sequence.

amid [387]

What's the problem?

3 0

3 years ago

Find the size of each of two samples (assume that they are of equal size) needed to estimate the difference between the proporti

hodyreva [135]

Answer:

The sample size n = 4225

Step-by-step explanation:

We will use maximum error formula = $\frac{z_{a} S.D}{\sqrt{n} }$

but we will find sample size "n"

$\sqrt{n} = \frac{z_{a} S.D}{maximum error}$

Squaring on both sides , we get

$n = (\frac{z_{a} S.D}{maximum error})^2$

Given 99% confidence interval (z value) = 2.56

given maximum error = 0.02

$n = (\frac{z_{a} p(1-p)}{maximum error})^2$

n≤ $(\frac{2.56X\frac{1}{2} }{0.02}) ^{2}$ ( here S.D = p(1-p) ≤ 1/2

on simplification , we get n = 4225

<u>Conclusion</u>:

The sample size of two samples is n = 4225

<u>verification</u>:-

We will use maximum error formula = $\frac{z_{a} S.D}{\sqrt{n} }$ = $\frac{2.56 1/2}{\ \sqrt{4225} }$ = 0.0196

substitute all values and simplify we get maximum error is 0.02

4 0

3 years ago