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3 years ago

Urgent help needed!

1 answer:

6 0

To write this in standard form, you need to eliminate the fraction in the coefficient of variable x. You can do this by multiplying 8 to the two sides of the equation:

8(y) = 8[(-5/8)x + 3]

8y = -5x + 24

Transpose the variable x to the other side:

5x + 8y = 24

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There is a recipe for barbecue sauce where the mixture is composed of four ingredients.in any quantity,the following is the make

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3 years ago

The probability that a certain make of car will need repairs in the first seven months is 0.9. A dealer sells three such cars. W

aleksandr82 [10.1K]

Answer:

0.9990 = 99.90% probability that at least one of them will require repairs in the first seven months.

Step-by-step explanation:

For each car, there are only two possible outcomes. Either they will require repair in the first seven months, or they will not. The probability of a car requiring repair in the first seven months is independent of other cars. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The probability that a certain make of car will need repairs in the first seven months is 0.9.

This means that $p = 0.9$ A dealer sells three such cars.

A dealer sells three such cars.

This means that $n = 3$

What is the probability that at least one of them will require repairs in the first seven months?

Either none will require repairs, or at least one will. The sum of the probabilities of these events is decimal 1. So

$P(X = 0) + P(X > 0) = 1$

We want P(X > 0). So

$P(X > 0) = 1 - P(X = 0)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{3,0}.(0.9)^{0}.(0.1)^{3} = 0.001$

Then

$P(X > 0) = 1 - P(X = 0) = 1 - 0.001 = 0.9990$

0.9990 = 99.90% probability that at least one of them will require repairs in the first seven months.

4 0

3 years ago

PLEASE PLEASE HELPPPP

Anastaziya [24]

You could expect about 1,248 students to play at least 4 hours every week.

Our tables have 100 students involved. All but 4 of the students are in the category of at least 4 hours. That is 96%.

Therefore, we simply need to multiply 0.96 by 1300 to get the estimated amount.

0.96 x 1300 = 1248

7 0

3 years ago

Read 2 more answers

What are the solutions of the equation (x – 3)2 + 2(x – 3) -8 = 0? Use u substitution to solve.

Andrej [43]

Answer:

x = -1 and x = 5

Step-by-step explanation:

<em>What are the solutions of the equation (x – 3)² + 2(x – 3) -8 = 0? Use u substitution to solve.</em>

<em />

(x – 3)² + 2(x – 3) -8 = 0 -------------------------------------------------------(1)

To solve this problem, we will follow the steps below;

let u = x-3

we will replace x-3 by u in the given equation:

(x – 3)² + 2(x – 3) -8 = 0

u² + 2u -8 = 0 ----------------------------------------------------------- --------------(2)

We will now solve the above quadratic equation

find two numbers such that its product gives -8 and its sum gives 2

The two numbers are 4 and -2

That is; 4×-2 = -8 and 4+(-2) = 2

we will replace 2u by (4u -2u) in equation (2)

u² + 2u -8 = 0

u² + 4u - 2u -8 = 0

u(u+4) -2(u+4) = 0

(u+4)(u-2) = 0

Either u + 4 = 0

u = -4

u-2 = 0

u = 2

Either u = -4 or u = 2

But u = x-3

x = u +3

when u = -4

x = u + 3

x = -4 + 3

x=-1

when u = 2

x = u + 3

x = 2 + 3

x=5

Therefore, x = -1 and x =5

6 0

3 years ago