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2 years ago

Does area and circumference mean the same thing

Mathematics

1 answer:

irga5000 [103]2 years ago

3 0

No area is length times width anx circumference is the area around the circule

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You go to the store and pick out 3 apples for $0.60 each, 2 bananas for $0.50 each, and 1 quart of yogurt for $4.50. At checkout

Thepotemich [5.8K]

Answer:

I'm not 100% sure but I think it's $6.20

Step-by-step explanation:

First you add up the apples which equals $1.80 then you add up the bananas which equals $1.00 then you add the yogurt together which amounts to $4.50. After that you add all of that together which totals to $7.30.

For the sake of finding the percentage we're gonna move the decimal point to the very end. ( so its 730.0). Now in order to find 15% we have to find 10%. To find 10%, you move the decimal point over one (73.00). So 10% of 730 is 73. 10% + 5% = 15%. And half of 10% is 5%. So, we cut 73 in half so now we have 36.5. Now we add 36.5 to 73 (because 10% + 5%=15%) I'm just gonna round 36.5 to 37, and 73+37= 110. Now we move the decimal point back so its $1.10. Now we subtract $1.10 from $7.30 which is equal to $6.20. So your answer is $6.20.

(I'm rlly bad at explaining things so sorry if this wasnt clear enough. Also I'm not the best at math but I guess I know percentages.)

8 0

2 years ago

List the steps that should be used to solve the equation f(x) = g(x) by graphing when f(x) = (1/2)² - 3 and g(x) = 3x + 5?

jolli1 [7]

value of x is: $x=\frac{-31}{12}$

Step-by-step explanation:

We need to solve the equation f(x)=g(x)

where $f(x)=(\frac{1}{2})^2-3$

and $g(x) = 3x + 5$

Solving to find f(x)=g(x)

Putting values of f(x) and g(x)

$f(x)=g(x)\\(\frac{1}{2})^2-3=3x + 5\\\frac{1}{4}-3=3x + 5\\Subtarct\,\,5\,\,on\,\,both\,\,sides:\\\frac{1}{4}-3-5=3x + 5-5\\\frac{1}{4}-8=3x\\Taking\,\,LCm\,\,on\,\,left\,\,side\\\frac{1-8*4}{4}=3x\\\frac{-31}{4}=3x\\Divide\,\,both\,\,sides\,\,by\,\,3\\x=\frac{-31}{4*3}\\x=\frac{-31}{12}$

So, value of x is: $x=\frac{-31}{12}$

The graph will be a straight line x= -2.58 or x = -31/12

Keywords: Composition of Functions

Learn more about Composition of Functions at:

#learnwithBrainly

7 0

3 years ago

Please Help! I will award Best Brainly Answer as well as 15 points

Llana [10]

ITS IS 8x-7y-5z=15 I THINK'

4 0

2 years ago

Simplify each expression. Assume that all variables are positive.

kozerog [31]

Q1. The answer is $\frac{8x^{3}y^{6} }{27}$

$( \frac{16 x^{5} y^{10}}{81x y^{2} } )^{ \frac{3}{4} }= ( \frac{16}{81}* \frac{ x^{5} }{x}* \frac{ y^{10} }{y^{2}} )^{ \frac{3}{4} } \\ \\ 
 \frac{ x^{a} }{ x^{b} }= x^{a-b} \\ \\ 
( \frac{16}{81}* \frac{ x^{5} }{x}*\frac{ y^{10} }{y^{2}} )^{ \frac{3}{4} }}=( \frac{16}{81 }* x^{5-1}* y^{10-2})^{ \frac{3}{4} }=( \frac{16}{81 }* x^{4}* y^{8})^{ \frac{3}{4} }= \\ \\ = (\frac{16}{18} )^{ \frac{3}{4} }*(x^{4})^{ \frac{3}{4} }*(y^{8})^{ \frac{3}{4} }=$
$\frac{(16)^{ \frac{3}{4} }}{(18)^{ \frac{3}{4} }}*(x^{4})^{ \frac{3}{4} }*(y^{8})^{ \frac{3}{4} }=\frac{( 2^{4} )^{ \frac{3}{4} }}{( 3^{4} )^{ \frac{3}{4} }}*(x^{4})^{ \frac{3}{4} }*(y^{8})^{ \frac{3}{4} } \\ \\ 
 (x^{a} )^{b} = x^{a*b} \\ \\ 
\frac{( 2^{4} )^{ \frac{3}{4} }}{( 3^{4} )^{ \frac{3}{4} }}*(x^{4})^{ \frac{3}{4} }*(y^{8})^{ \frac{3}{4} } = \frac{ 2^{4* \frac{3}{4} } }{ 3^{4* \frac{3}{4} } } * x^{4* \frac{3}{4} } * y^{8*\frac{3}{4}} = \frac{ 2^{3} }{ 3^{3} } * x^{3} *y^{6} =$
$= \frac{8x^{3}y^{6} }{27}$

Q2. The answer is 1/16

$(-64) ^ \frac{-2}{3} =(-1* 2^{6} ) ^ \frac{-2}{3}=(-1)^ \frac{-2}{3} *(2^{6} ) ^ \frac{-2}{3} \\\\x^{-a} = \frac{1}{ x^{a} } \\\\(-1)^ \frac{-2}{3} *(2^{6} ) ^ \frac{-2}{3} = \frac{1}{(-1)^ \frac{2}{3}} *\frac{1}{(2^{6})^ \frac{2}{3}} \\ \\ (x^{a} )^{b}=x^{a*b} \\\\x^{ \frac{a}{b} = \sqrt[b]{ x^{a} } } \\ \\ 
$
$\frac{1}{(-1)^ \frac{2}{3}} *\frac{1}{2^{6*\frac{2}{3}}} = \frac{1}{ \sqrt[3]{(-1)^{2} } } * \frac{1}{ 2^{4} } = \frac{1}{ \sqrt[3]{1} } * \frac{1}{16} = \frac{1}{1} * \frac{1}{16}= \frac{1}{16}$

Q3. The answer is $a^{ \frac{7}{6} }$

$a^{ \frac{2}{3} } * a^{ \frac{1}{2} } \\ \\ 
 x^{a}* x^{b} =x^{a+b} \\ \\ 
a^{ \frac{2}{3} } * a^{ \frac{1}{2} }= a^{ \frac{2}{3} + \frac{1}{2} } =a^{ \frac{2*2}{3*2} + \frac{1*3}{2*3} }=a^{ \frac{4}{6} + \frac{3}{6} }=a^{ \frac{4+3}{6} }=a^{ \frac{7}{6} }$

7 0

2 years ago

Help me with these 2 questions ;(

vichka [17]

Answer:

1.) A' = (4,-4)

B' = (2,-4)

C' = (2,-2)

D' = (4,-2)

2.) A' = (-1,5)

B' = (-2,1)

C' = (0,1)

Hope this helps!

And please mark as brainliest!

4 0

2 years ago