For this case we must simplify the following expression:
We must add similar terms taking into account that:
Thus, the simplified expression is:
Answer:
Answer:
The width and length of rectangle is 12.728 m
Step-by-step explanation:
Let the length of the rectangle = L
let the width of the rectangle = W
The subjective function is given by;
F(p) = 2(L + W)
F = 2L + 2W
Area of the rectangle is given by;
A = LW
LW = 162 ft²
L = 162 / W
Substitute in the value of L into subjective function;
Take the second derivative of the function, to check if it will given a minimum perimeter
Determine the critical points of the first derivative;
df/dw = 0
L = 162 / 12.728
L = 12.728 m
Therefore, the width and length of rectangle is 12.728 m