Answer:
Answer in the pic with steps
Hope it helps
Answer:
percentage change from 1960 to 1970 =( 0.11 ÷0.25 ) × 100
= 44 %
Percentage change from 1970 to 1980 =( 0.83 ÷ 0.36) × 100
= 230.55%
percentage change from 1980 to 1990 = ( 0.16 ÷ 1.19) × 100
= 13.44%
percentage change from 1990 to 2000 = (- 0.09 ÷ 1.35) × 100
= -6.667%
Step-by-step explanation:
Item : 1960 1970 1980 1990 2000
gallon: $0.25 $0.36 $1.19 $1.35 $1.26
change : 0.36 - 0.25 = 0.11
percentage change from 1960 to 1970 =( 0.11 ÷0.25 ) × 100
= 44 %
Percentage change from 1970 to 1980 =( 0.83 ÷ 0.36) × 100
= 230.55%
percentage change from 1980 to 1990 = ( 0.16 ÷ 1.19) × 100
= 13.44%
percentage change from 1990 to 2000 = (- 0.09 ÷ 1.35) × 100
= -6.667%
Answer: $5.00 is the range
Step-by-step explanation: Range is the largest number subtracted by the smallest, so $6 - $1 is $5.
Answer:
81π ft³
Step-by-step explanation:
If the diameter is 6 ft, the radius is 3 ft.
The volume is V = (area of base)(height).
Here, V = (π[3 ft]²)(9 ft) = 81π ft³
Rewriting the equation as a quadratic equation equal to zero:
x^2 - x - 30 = 0
We need two numbers whose sum is -1 and whose product is -30. In this case, it would have to be 5 and -6. Therefore we can also write our equation in the factored form
(x + 5)(x - 6) = 0
Now we have a product of two expressions that is equal to zero, which means any x value that makes either (x + 5) or (x - 6) zero will make their product zero.
x + 5 = 0 => x = -5
x - 6 = 0 => x = 6
Therefore, our solutions are x = -5 and x = 6.