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3 years ago

Whats the step by step answer to this equation i got -25 but its supposed to be positive not negative

Mathematics

2 answers:

bearhunter [10]3 years ago

8 0

Answer:

x = 25

Step-by-step explanation:

Given

- $\frac{6}{5}$ x = - 30 ( multiply both sides by 5 to clear the fraction )

- 6x = - 150 ( divide both sides by - 6 )

x = 25

andreev551 [17]3 years ago

6 0

Answer:

Step-by-step explanation:

- 6/5x = -30 ⇒ multiply both sides by -1
6/5x = 30 ⇒ multiply both sides by 5
6x = 5*30
x = 150/6 ⇒ divide both sides by 6
x = 25 ⇒ answer

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What is 3x - y = -4 2x - y = -10 Using substitution

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3 years ago

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Step-by-step explanation:

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4 0

2 years ago

A wire that is 22 feet long connects the top of a pole to the ground. The wire is attached to the ground at a point that is 10 f

krok68 [10]

✰ Concept Used :-

⠀

In this question, we can clearly observer that the diagram shows a right angled triangle. And, we have been provided with the value of base, and the value of hypotenuse, using the pythagoras theorem, now we can easily find out the value of the perpendicular i.e. the value of the side h. According to the pythagoras theorem, square of hypotenuse is equal to the sum of square of perpendicular and square of side respectively. Therefore, square of side is equal to the difference of square of hypotenuse and square of perpendicular.

⠀

✰ Given Information :-

⠀

Hypotenuse = 22 ft.
Base = 10 ft.

⠀

✰ To Find :-

⠀

The value of side or the perpendicular

⠀

✰ Formula Used :-

⠀

$\star \: \underline{ \boxed{ \purple { \sf {Side}^{2} = {Hypotenuse}^{2} - {Base}^{2} }}} \: \star$

⠀

✰ Solution :-

⠀

$\sf \longrightarrow {Side}^{2} = {(22 \: ft)}^{2} - {(10 \: ft)}^{2} \: \: \: \\ \\ \\ \sf \longrightarrow {Side}^{2} = {484 \: ft}^{2} - {100 \: ft}^{2} \: \: \: \: \: \: \\ \\ \\ \sf \longrightarrow {Side}^{2} = {384 \: ft}^{2} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \sf \longrightarrow {Side}^{} = \sqrt{ {384 \: ft}^{2} } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \sf \longrightarrow {Side}^{} = \underline{ \boxed{ \frak{ \green{19.60 \: ft}}}} \: \star \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\$

Thus, option B. 19.60 ft. is the correct option.

⠀

$\underline{\rule{230pt}{2pt}} \\ \\$

4 0

2 years ago