1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nostrana [21]
4 years ago
5

Why is it difficult to see colors outside at night?

Physics
2 answers:
IgorLugansk [536]4 years ago
3 0

I think it is B hope this helps

God Bless

Reika [66]4 years ago
3 0
Both rods and cones are sensitive to light. The difference between them is that the rods allow us to see<span> in very dim light but don't permit detection of </span>color<span>, while the cones let us </span>see color<span> but they don't work in dim light. When it gets dark the cones lose their ability to respond to light</span>
You might be interested in
On a frictionless horizontal air table, puck A (with mass 0.254 kg ) is moving toward puck B (with mass 0.367 kg ), which is ini
irinina [24]

Answer:

v_a=0.8176 m/s

\Delta K=0.07969 J - 0.0849 J = -0.00521 J

Explanation:

According to the law of conservation of linear momentum, the total momentum of both pucks won't be changed regardless of their interaction if no external forces are acting on the system.

Being m_a and m_b the masses of pucks a and b respectively, the initial momentum of the system is

M_1=m_av_a+m_bv_b

Since b is initially at rest

M_1=m_av_a

After the collision and being v'_a and v'_b the respective velocities, the total momentum is

M_2=m_av'_a+m_bv'_b

Both momentums are equal, thus

m_av_a=m_av'_a+m_bv'_b

Solving for v_a

v_a=\frac{m_av'_a+m_bv'_b}{m_a}

v_a=\frac{0.254Kg\times (-0.123 m/s)+0.367Kg (0.651m/s)}{0.254Kg}

v_a=0.8176 m/s

The initial kinetic energy can be found as (provided puck b is at rest)

K_1=\frac{1}{2}m_av_a^2

K_1=\frac{1}{2}(0.254Kg) (0.8176m/s)^2=0.0849 J

The final kinetic energy is

K_2=\frac{1}{2}m_av_a'^2+\frac{1}{2}m_bv_b'^2

K_2=\frac{1}{2}0.254Kg (-0.123m/s)^2+\frac{1}{2}0.367Kg (0.651m/s)^2=0.07969 J

The change of kinetic energy is

\Delta K=0.07969 J - 0.0849 J = -0.00521 J

3 0
3 years ago
A cyclist has a constant speed of 12 m/s. What is the magnitude of the displacement of the cyclist after 18 seconds?
Katyanochek1 [597]

Answer:

216 m

Explanation:

Assuming a straight line:

Δx = vt

Δx = (12 m/s) (18 s)

Δx = 216 m

7 0
3 years ago
All ecosystems need<br> and<br> in order to survive.
Triss [41]

Answer:

An ecosystem is a community of living things and their non-living environment, and may be as large as a desert or as small as a puddle. An ecosystem must contain producers, consumers, decomposers, and dead and inorganic matter. All ecosystems require energy from an external source – this is usually the sun.

Explanation:

4 0
3 years ago
Explain how it is possible for two different elements to have the same mass number
Leya [2.2K]

Atoms from two different elements may have the same number of neutrons, but never the same number of protons

8 0
3 years ago
Read 2 more answers
I'M GIVING 95POINTS PLZ HELP!!
Travka [436]

#1

initial height = 25000 ft

as we know that

1 ft = 0.3048 m

so we have

H = 25000(0.3048) = 7620 m

#2

If mass of the man = 90 kg

now the initial potential energy is given as

U = mgh

U = (90)(9.8)(7620)

U = 6.72 \times 10^6 J

#3

Gravitational force that is acting on it is given by

F = mg

F = 90(9.8) = 882 N

so this is the force by which earth is attracting him towards it as we can see due to this force the man is accelerating towards the earth

#4

As we know that gravitational force is given by

F = \frac{GMm}{r^2}

here we know that

r = R + h

R = radius of earth (6.37 \times 10^6 m)

h = 7620 m

now we have acceleration at that point is

a = \frac{F}{m}

a = \frac{GM}{r^2}

a = \frac{(6.67\times 10^{-11})(5.98 \times 10^{24})}{(6.37 \times 10^6 + 7620)^}

a = 9.806 m/s^2

#5

by energy conservation we have

KE = PE

\frac{1}{2}mv^2 = mgh

v^2 = 2gh

v^2 = 2(9.8)(7620)

v = 386.5 m/s

#6

final speed due to wind resistance is 150 mph

now we know that

1 mile = 1609 meter

so this speed in m/s is given as

150 mph = 150(\frac{1609 m}{3600 s})

v = 67 m/s

#7

No Luke is not accelerating when his speed is 150 mph

because at this speed his velocity will become constant

and since there is no change in velocity so his acceleration will become zero

#8

since at 150 mph the acceleration of Luke is zero

so net force on him must be zero

so we will have

wind force = weight or force due to earth

F_{wind} = 882 N

#9

If there is no wind resistance then there will be energy conservation

so KE = PE

KE = 6.72 \times 10^6 J

#10

Net will reduce the velocity of luke to be zero by taking long time

As we know that force on a system is given by

F = \frac{\Delta P}{\Delta t}

so if we increase the time interval here then we will have less force

so Luke will unhurt due to more time to decrease his speed to be zero

5 0
3 years ago
Other questions:
  • You throw a baseball straight up in the air, it moves vertically upwards, becomes stationary and then falls back to your hand at
    13·1 answer
  • What is the main determining factor in defining boundaries between layers of earth's atmosphere?
    7·2 answers
  • Which of the following types of pollution is NOT linked to coal-burning power plant emissions?
    8·1 answer
  • A pair of bullocks exerts a force of 140 N on a plough. The field being ploughed is 15 m long. How much work is done in ploughin
    8·2 answers
  • In principle, when you fire a rifle, the recoil should push you backward. How big a push will it give? Let’s find out by doing a
    15·1 answer
  • A person is standing on a spring bathroom scale on the floor of an elevator which is moving up and slowing down at the rate of 2
    12·2 answers
  • A car of mass 1500kg is towing a trailer if mass 1100kg alonf a level road. The acceleration of the car is 1.30m/s.
    15·1 answer
  • A motor cycle travelling at 10 m/s accelerates at 4m/s for 8s.<br>what is it final velocity? ​
    12·2 answers
  • Define upthrust simply (don't copy)​
    6·1 answer
  • A basketball is tossed upwards with a speed of 5.0 m/s. We can ignore air resistance. What is the maximum height reached by the
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!