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4 years ago

8

A 110 kg crate is pulled along a level surface by an engine. The coefficient of kinetic friction between the crate and the surfa

ce is 0.585. How much power must the engine deliver to move the crate at a constant speed of 7.59 m/s? The acceleration due to gravity is 9.8 m/s 2 . Answer in units of W.

1 answer:

Leno4ka [110]4 years ago

3 0

Answer:

Net power will be 1150.637 watt

Explanation:

We have given mass of the crate m = 110 kg

Coefficient of friction $\mu =0.585$

Acceleration due to gravity $g=9.8m/sec^2$

Constant speed $v=7.59m/sec$

Force applied $F=ma=110\times 7.59=834.9N$

Frictional force $f=\mu mg=0.585\times 110\times 9.8=630.63N$

So net force $=834.9-630.6=204.3N$

Power is given by $P=Fv=204.3\times 7.59=1550.637Watt$

So net power will be 1550.637 watt

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