Question

A 110 kg crate is pulled along a level surface by an engine. The coefficient of kinetic friction between the crate and the surface is 0.585. How much power must the engine deliver to move the crate at a constant speed of 7.59 m/s? The acceleration due to gravity is 9.8 m/s 2 . Answer in units of W.

Answer 1

Answer:

Net power will be 1150.637 watt

Explanation:

We have given mass of the crate m = 110 kg

Coefficient of friction $\mu =0.585$

Acceleration due to gravity $g=9.8m/sec^2$

Constant speed $v=7.59m/sec$

Force applied $F=ma=110\times 7.59=834.9N$

Frictional force $f=\mu mg=0.585\times 110\times 9.8=630.63N$

So net force $=834.9-630.6=204.3N$

Power is given by $P=Fv=204.3\times 7.59=1550.637Watt$

So net power will be 1550.637 watt