Question

If a = 4 units and b = 3 units, the length of the diagonal of the outside square rounded to the nearest tenth is

Answer 1

Use pythagorean theorem
a^2+b^2=c^2
4^2+3^2=c^2
16+9=c^2
25=c^2
c=5
hope this helps!

Answer 2

Answer with explanation:

Two Adjacent Sides of Rectangle are, a=4 units, and , b=3 units

Diagonal of rectangle

   $=\sqrt{4^2+3^2}\\\\=\sqrt{25}\\\\=5$

→Diagonal of Rectangle = 5 units, which is the side of Square lying outside the rectangle.

Length of Diagonal of Square

          $=\sqrt{5^2+5^2}\\\\=\sqrt{50}\\\\=5\sqrt{2}$

Diagonal of  Square formed from rectangle of side 4 cm and 3 cm =5 × 1.414

                                          = 7.070 units

                                           =7.07 units