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2 years ago

Is it possible to draw a triangle with these measurements 90° 60° and 60°

Mathematics

1 answer:

lina2011 [118]2 years ago

7 0

Answer:

Step-by-step explanation:

The angles of a triangle must always add up to 180 degrees.

90 + 60 + 60 = 210 degrees.

Therefore it would not be possible to draw a triangle with these values.

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Find an ordered pair , x y that is a solution to the equation. 3x-y=1

NemiM [27]

Answer:

2,5

Step-by-step explanation:

2,5 is just one of the many solutions to this problem. you can just take a random number for x, for example 2. your equation will look like this 3(2)-y=1. now you just solve for y. 3x2=6. 6-1=5. so y=5.

3 0

3 years ago

How many decimal places are in the product of 1.91 and 2.3?

san4es73 [151]

Answer:

Step-by-step explanation:

2+1 = 3

8 0

2 years ago

Read 2 more answers

The cost of a student ticket to the school play is $7. Write an equation that correctly relates the total cost, c, for a particu

Mazyrski [523]

C = $7s
independent variable ie the changing variable is s
dependent variable ie the non changing variable is c

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3 years ago

Read 2 more answers

Two boats leave the same place at the same time. The first boat heads due north at 10 kilometers per hour. The second boat heads

Maksim231197 [3]

Answer:

18.87 km/hr

Step-by-step explanation:

First boat is heading North with a speed of 10 km/hr.

Second boat is heading West with a speed of 16 km/hr.

Time for which they move = 2.5 hours

To find:

The speed at which the distance is increasing between the two boats.

Solution:

Let the situation be represented by the attached diagram.

Their initial position is represented by point O from where they move towards point A and point B respectively.

$Distance = Speed \times Time$

$Distance\ OA = 10 \times 2.5 = 25\ km$

$Distance\ OB = 16 \times 2.5 = 40\ km$

We can use Pythagorean Theorem to find the distance AB.

AB is the hypotenuse of the right angled $\triangle AOB$ .

According to Pythagorean theorem:

$\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}\\\Rightarrow AB^{2} = OA^{2} + OB^{2}\\\Rightarrow AB^2 = 25^2 + 40^2\\\Rightarrow AB^2 = 2225^2\\\Rightarrow AB^2 \approx 47.17\ km$

The speed at which distance is increasing between the two boats is given as:

$\dfrac{47.17}{2.5} \approx 18.87\ km/hr$

4 0

2 years ago

What is the least common denominator of 1/5 and 7/10

il63 [147K]

Answer:

2/10 7/10

Step-by-step explanation:

7 0

3 years ago