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Vladimir79 [104]
4 years ago
15

what is the total number of grams of NaOH needed to react completely with 196 grams of H2 SO4? regents

Chemistry
1 answer:
8090 [49]4 years ago
3 0

Answer:

160 g

Explanation:

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

For H_2SO_4:-  

Mass of H_2SO_4 = 196 g

Molar mass of H_2SO_4 = 98 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{196\ g}{98\ g/mol}

Moles\ of\ Sulfuric\ acid= 2\ mol

According to the given reaction:

2NaOH+H_2SO_4\rightarrow Na_2SO_4+2H_2O

1 mole of sulfuric acid reacts with 2 moles of NaOH

So,  

2 moles of sulfuric acid reacts with 2*2 moles of NaOH

Moles of NaOH must react = 4 moles

Molar mass of NaOH = 40 g/mol

<u>Mass = Moles*molar mass = 4\times 40\ g = 160 g</u>

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