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Murrr4er [49]
3 years ago
9

What is the volume of 3.40 mol of gas at 33.3C and 22.2atm of pressure

Chemistry
1 answer:
Luda [366]3 years ago
5 0
The volume of 3.40 mol of gas at 33.3 C and 22.2 atm of pressure is 3.85 liter of gas. This problem can be solved by using the PV=nRT or V= nRT/V equation which is the relation between the molar volume, the temperature, and the pressure of gas. In this formula, P is the pressure, R is the universal gas constant ( 0.0821 atm L/mol K), n is the molecule amount, V is the molecular volume, and T is the temperature. The temperature used in this formula must be in Kelvin, therefore we have to convert the Celcius temperature into Kelvin temperature (33.3 C = 306.45 K).
<span>The calculation for the problem above: 3.4*0.0821*306.45/22.2 = 3.85 liter of gas.</span>
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A engineer measures the peak power output is 0.3227MW what is the peak power output in kilowatts ?
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<h3>Answer:</h3>

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<h3>Explanation:</h3>
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In this case, we are required to convert 0.3227 MW to kilowatts

We need to know that;

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Therefore;

10^3 kW = 1 MW

Therefore, the suitable conversion factor is 10^3kW/MW

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0.3227 MW is equivalent to;

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