Intertidal zone-Referred sometimes as foreshore,which is area above water at low tide and under water at high tide
Answer:
16) 6 electrons
17) 6 protons
18) 6 neutrons
19) 4 electrons
20) 6
Explanation:
There are 6 electrons on the rings in total and 6 protons inside the nucleus. If you count the black cir les, there are 6 of them so there are 6 neutrons. Knowing that the inner ring can only hold 2 electrons the most, 6-2= 4. So there are 4 electrons on the outer ring. Knowing that you can get the atomic number based on the number of protons an atom have, the at pool mic number would be 6.
Photogenic traits are determined by multiple GENES received from each parent.
Answer:
Glucose present as monomers within the cell will exert more osmotic pressure than a single glycogen molecule, resulting in endosmosis and the lysing of cells.
Also, the presence of free glucose molecules will result in increase in weight of the liver due to lack of efficient packing as in glycogen as well as the association ofnthe glucose molecules with water molecules.
Explanation:
Glycogen is a polysaccharide composed of glucose monomer units linked to Each other by α-1,4-glycosidic binds. α-1,6-branches arises at about every 10th glucose residue in the straight chain. Thus animals more glucose molecules to be stored within a much smaller space, thereby incresing the bulkiness of glycogen. Glycogen molecules are insoluble in the aqueous medium of the cell because it doesn't have enough free polar groups to participate in hydrogen bonding with water and are stored as granules and therefore do not affect the water potential or osmotic balance of the cell.
On the other hand, glucose molecules are highly soluble in water because it has many free polar -OH grours that form hydrogen bonds with water. If the glucosyl residues in large numbers of glycogen molecules were replaced with an equivalent number of molecules of free glucose, the free glucose will exert a high osmotic pressure inside the cell, causing the entry of water in the cell by endosmosis resulting in swelling and lysis ofnthe cell. Also, the space occupied by these free glucose units within the cell will be much larger than that of glycogen whichmenables efficient packing ofthe glucose molecules.
The correct answer is D) The codon AUG must be identified.
What must occur for protein translation to begin is that the codon AUG must be identified.
The process starts when the 5AUG or start codon is identified. In the polypeptide chain, the 5AUG is the first amino acid. We are talking about Transition, the process when the genetic code in an RNA molecule has to be decoded in a polypeptide chain in order to deliver an amino acid sequence. In this complex transition system, there are important components included such as ribosomes, transfer RNA, and mRNA.
