Each sheet of metal is 0.1 inches thick. If Zoe stacks 3 sheets on top of each other, how thick will the stack be?

Which best describes the graph of the function f(x) = -5x ?

il63 [147K]

Answer:

This is a simple slope intercept form equation: y=ax+b

Where a is the slope and b is the y-intercept, but in this problem the y-intercept is 0 so it is no shown.

The line on the graph would be negative (downward) because of the negative and would be going down by a slope of -5.

-down 5 over 1 ( rise over run )

7 0

3 years ago

The slope of the line that passes through points -2,3 and 10,3 is

Ray Of Light [21]

Answer:

i gave you the slope and if its a function

Step-by-step explanation:

it a function

Slope (m) = ΔYΔX= 0

θ = arctan( ΔY )ΔX= 0°

ΔX = 10 – -2 = 12

ΔY = 3 – 3 = 0

Distance (d) = √ΔX2 + ΔY2 = √144 = 12

Equation of the line:

y = 0x + 3

When x=0, y = 3

3 0

3 years ago

Read 2 more answers

Find the sum of the first 6 terms in the sequence -5 -25 -125 -625

sashaice [31]

This is a geometric sequence, so use the formula for the sum of a geometric sequence:
Sum = (a(r^n - 1))/(r - 1)
where a is the first term, -5
r is the common ratio, 5
and n is the number of terms

Thus,
Sum = ((-5)(5^6 - 1))/(5-1) = -19530

5 0

3 years ago

PLEASEEE HELP IM REALLY CONFUSED ;( ILL GIVE BRAINLIEST TO BEST ANSWR

Paladinen [302]

D.........................................

4 0

2 years ago

Suppose that the amount of time T a customer spends in a bank is exponentially distributed with an average of 10 minutes. What i

Bad White [126]

Answer:

The probability that a customer will spend more than 15 minutes total in the bank, given that the customer has already waited over 10 minutes is 0.6065.

Step-by-step explanation:

The random variable T is defined as the amount of time a customer spends in a bank.

The random variable T is exponentially distributed.

The probability density function of a an exponential random variable is:

$f(x)=\lambda e^{-\lambda x};\ x>0$

The average time a customer spends in a bank is β = 10 minutes.

Then the parameter of the distribution is:

$\lambda=\frac{1}{\beta}=\frac{1}{10}=0.10$

An exponential distribution has a memory-less property, i.e the future probabilities are not affected by any past data.

That is, P (X > s + x | X > s) = P (X > x)

So the probability that a customer will spend more than 15 minutes total in the bank, given that the customer has already waited over 10 minutes is:

P (X > 15 | X > 10) = P (X > 5)

$\int\limits^{\infty}_{5} {f(x)} \, dx =\int\limits^{\infty}_{5} {\lambda e^{-\lambda x}} \, dx\\=\int\limits^{\infty}_{5} {0.10 e^{-0.10 x}} \, dx\\=0.10\int\limits^{\infty}_{5} {e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10}|^{\infty}_{5}\\=[-e^{-0.10 \times \infty}+e^{-0.10 \times 5}]\\=0.6065$

Thus, the probability that a customer will spend more than 15 minutes total in the bank, given that the customer has already waited over 10 minutes is 0.6065.

8 0

2 years ago