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ivolga24 [154]
3 years ago
9

Please help me ASAP!

Mathematics
2 answers:
spin [16.1K]3 years ago
7 0

Answer:

10

Step-by-step explanation:

2x+46+3x-6 = 90

5x + 40 = 90

5x = 50

x =10

melamori03 [73]3 years ago
4 0
The answer is 10 I think I’m right
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In a circle C, r = 32 units. What is the area of circle c
Tcecarenko [31]
The answer is A≈3217u²

For the area of circles, multiply \pi×radius² 
4 0
4 years ago
Please help I will really appreciate it
Veronika [31]
Hi!
Where’s the question.
8 0
2 years ago
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What is -7(x-2)=1=15-7x
Soloha48 [4]

Answer:

0

Step-by-step explanation:

Simplifying

-7(x + -2) + 1 = 15 + -7x

Reorder the terms:

-7(-2 + x) + 1 = 15 + -7x

(-2 * -7 + x * -7) + 1 = 15 + -7x

(14 + -7x) + 1 = 15 + -7x

Reorder the terms:

14 + 1 + -7x = 15 + -7x

Combine like terms: 14 + 1 = 15

15 + -7x = 15 + -7x

Add '-15' to each side of the equation.

15 + -15 + -7x = 15 + -15 + -7x

Combine like terms: 15 + -15 = 0

0 + -7x = 15 + -15 + -7x

-7x = 15 + -15 + -7x

Combine like terms: 15 + -15 = 0

-7x = 0 + -7x

-7x = -7x

Add '7x' to each side of the equation.

-7x + 7x = -7x + 7x

Combine like terms: -7x + 7x = 0

0 = -7x + 7x

Combine like terms: -7x + 7x = 0

0 = 0

Solving

0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

3 0
3 years ago
Can you please answer this question
tamaranim1 [39]
3tan^{2} \theta +7sec\theta=3
First I converted the equation terms into sine and cosine.
tan^{2}\theta = \frac{sin^{2}\theta}{cos^{2}\theta} and sec\theta= \frac{1}{cos\theta}
Substitution:
\frac{3sin^2\theta}{cos^2\theta} + \frac{7}{cos\theta} =3
Common Denominator Created:
\frac{3sin^2\theta}{cos^2\theta} + \frac{7cos\theta}{cos^2\theta} =3
Multiply each term by the LCD:
3sin^2\theta+7cos\theta=3cos^2\theta
Substitution: Recall ⇒sin^2\theta =1-cos^2\theta 
3(1-cos^2\theta)+7cos\theta=3cos^2\theta
Distribute and collect all terms on one side:
6cos^2\theta-7cos\theta-3=0
Factor and set each factor equal to 0:
(2cos\theta-3)(3cos\theta+1)=0
2cos\theta-3=0⇒theta=cos^{-1} \frac{3}{2}
3cos\theta+1=0⇒theta=cos^{-1} \frac{-1}{3}
The 2nd factor provides only possible answer 109.5 degrees

4 0
3 years ago
Helen has 48 cubic inches of clay to make a solid square right pyramid with a base edge measuring 6 inches. Which is the slant h
Nikitich [7]

Answer: 5 inches


Step-by-step explanation:

Given: Volume of clay = 48 cubic inches

If we make a solid square right pyramid with a base edge a= 6 inches.

Then its base area = a^2=6^2=36\ inches^2

we know that volume of square right pyramid=\frac{1}{3}\times\ a^2h

Therefore, volume of square right pyramid made by all of clay=\frac{1}{3}\times\ a^2h=48 cubic inches

\Rightarrow\frac{1}{3}\times\ (36)\times\ h=48\\\Rightarrow12h=48\\\Rightarrow\ h=4\ inches.....\text{[Divide 12 on both sides]}

Now, slant height l=\sqrt{(\frac{a}{2})^2+h^2}

\\\Rightarrow\ l=\sqrt{3^2+4^2}\\\Rightarrow\ l=\sqrt{9+16}\\\rightarrow\ l=\sqrt{25}\\\Rightarrow\ l=5

The slant height of the pyramid if Helen uses all the clay=5 inches

5 0
3 years ago
Read 2 more answers
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