the only like-terms are on the right-hand-side, since the left-hand-side has only 1 term anyway.
Answer:
Answer is 0.696
Step-by-step explanation:
The sum number of sets possible for no two students to have the same birthday in a class of 30 is:
=30 * (30-1)/2
= 435.
Now, there are 365 days in a year. Therefore, the probability of students having a birthday on a different date would be 364/365. Now there are a number of combination, to be exact 870 combinations.
So, the probability that no two students having the same birthday is:
(364/365)^435 = 0.303.
Now, the probability that two students would have their birthdays on the same equal date would be:
1-0.303 = 0.696 or 70%
Answer:
Step-by-step explanation:
<u>Initial perimeter:</u>
<u>Perimeter after change:</u>
<u>Change in perimeter:</u>
<u>Percent change:</u>
Answer:
A
Step-by-step explanation:
note that these are the factors of a difference of squares
• a² - b² = (a + b)(a - b), hence
(x + 13)(x - 13)= x² - 13² = x² - 169 → A
