The equation of the given line above is y=3x-1. The slope of the line is 3/1 (3x) and the y-intercept which is where the line crosses the y-axis is (0,-1) When you plug these parameters into the equation you will get the equation y=3x-1
Step-by-step explanation:
The system of linear equations are , (i) y = 2x and (ii) y = x + 1 . We will find some coordinates and then we will plot its graph. The point where both Graphs will meet will be the solution of the graph .
<u>•</u><u> </u><u>Findin</u><u>g</u><u> </u><u>coordinates</u><u> </u><u>of </u><u>Equ</u><u>ⁿ</u><u> </u><u>(</u><u>i</u><u>)</u><u> </u><u>:</u><u>-</u>
Step 1 : <u>Put</u><u> </u><u>x</u><u> </u><u>=</u><u> </u><u>0</u><u> </u><u>:</u><u>-</u>

Step 2: <u>Put</u><u> </u><u>x</u><u> </u><u>=</u><u> </u><u>1</u><u> </u><u>:</u><u>-</u><u> </u>


<u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u>
<u>•</u><u> </u><u>Finding</u><u> </u><u>coord</u><u>inates</u><u> </u><u>of</u><u> </u><u>equⁿ</u><u> </u><u>(</u><u>ii</u><u>)</u><u> </u><u>:</u><u>-</u>
Step 1 : Put x = 0 :-

Step 2: Put x = 1 :-


Now plot these points on the graph Taking appropriate scale . Refer to the attachment in graph . From graph the Solution is (1,2) .
Answer:
Two congruent figures
Step-by-step explanation:
Here we have to use the definition of congruent.
Congruent means equal to each other.
Example.
If the two triangles said be congruent, their corresponding angles and corresponding sides are equal.
They will have to same size of the sides and same measure of angles.
Two equal polygons, that is two congruent figures.
Hope this will help you.
Thank you.
Here, I've attached a picture of the triangle that accompanies this explanation.
cot = = =
Now view the triangle.
PS. Angle theta will have a coordinate of (-, +) because it is in quadrant II.
sin of the angle would be opposite/hypotenuse, so sin =
cos of the angle would be adjacent/hypotenuse, so cos =
tan of the angle would be opposite/adjacent, so tan =