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BabaBlast [244]
3 years ago
14

Steve and Michelle Neely are celebrating their 30th anniversary by having a reception at a local reception hall. They have budge

ted $ 4 comma 500$4,500 for their reception. If the reception hall charges a $ 60$60 cleanup fee plus $ 38$38 per​ person, find the greatest number of people that they may invite and still stay within their budget.
Steve and Michelle can invite at most
___________________ people to the reception.
​(Round down to the nearest whole​ person.)
Mathematics
2 answers:
lord [1]3 years ago
8 0
4 500-60 = 4 440
4 440/38 = 116.8
At most they would be able to invite 116 people to the reception with their budget.  
andre [41]3 years ago
8 0
116.8 people but of course there can't be 116.8 people so the answer is 116 answer
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A cone with radius 5 units is shown below. Its volume is 105 cubic units. Find the height of the cone.
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Answer:

height of the cone  = 4.01273885 units

Step-by-step explanation:

Volume of a cone(V) is given by:

V = \frac{1}{3} \pi r^2h             ....[1]

where,

r is the radius and h is the height of the cone.

As per the statement:

A cone with radius 5 units and ts volume is 105 cubic units

⇒r = 5 units and V = 105 cubic units

Substitute these given values and use \pi = 3.14 in [1] we have;

105 = \frac{1}{3} \cdot 3.14 \cdot 5^2 \cdot h

Multiply both sides by 3 we have;

⇒315 = 78.5 \cdot h

Divide both sides by 78.5 we have;

4.01273885 = h

or

h = 4.01273885 units

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4 years ago
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Find the height h of the cone. Round your answer to the nearest tenth.
denis-greek [22]

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around 36 in (round 35.98 to nearest tenth)

Step-by-step explanation:

6 0
2 years ago
The numbers of teams remaining in each round of a single-elimination tennis tournament represent a geometric sequence where an i
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Answer:

a_n = 128\bigg(\dfrac{1}{2}\bigg)^{n-1}

Step-by-step explanation:

We are given the following in the question:

The numbers of teams remaining in each round follows a geometric sequence.

Let a be the first the of the geometric sequence and r be the common ration.

The n^{th} term of geometric sequence is given by:

a_n = ar^{n-1}

a_4 = 16 = ar^3\\a_6 = 4 = ar^5

Dividing the two equations, we get,

\dfrac{16}{4} = \dfrac{ar^3}{ar^5}\\\\4}=\dfrac{1}{r^2}\\\\\Rightarrow r^2 = \dfrac{1}{4}\\\Rightarrow r = \dfrac{1}{2}

the first term can be calculated as:

16=a(\dfrac{1}{2})^3\\\\a = 16\times 6\\a = 128

Thus, the required geometric sequence is

a_n = 128\bigg(\dfrac{1}{2}\bigg)^{n-1}

4 0
3 years ago
Consider a convex hexagon in which all pairs of opposite sides are parallel. Prove that if one pair of opposite sides have equal
hjlf

A pair of the opposite sides of a hexagon has equal length and this is proved below.

<h3>How to illustrate the hexagon?</h3>

It should be noted that a hexagon is a polygon that has six sides.

In this case, it has 6 sides.

The total angles will be:

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A diagram is attached to illustrate the pair of parallel sides.

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