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BabaBlast [244]
3 years ago
14

Steve and Michelle Neely are celebrating their 30th anniversary by having a reception at a local reception hall. They have budge

ted $ 4 comma 500$4,500 for their reception. If the reception hall charges a $ 60$60 cleanup fee plus $ 38$38 per​ person, find the greatest number of people that they may invite and still stay within their budget.
Steve and Michelle can invite at most
___________________ people to the reception.
​(Round down to the nearest whole​ person.)
Mathematics
2 answers:
lord [1]3 years ago
8 0
4 500-60 = 4 440
4 440/38 = 116.8
At most they would be able to invite 116 people to the reception with their budget.  
andre [41]3 years ago
8 0
116.8 people but of course there can't be 116.8 people so the answer is 116 answer
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Doug’s family buys 7 postcards while on vacation. Each postcard costs 0.25$ including tax. How can Doug use the number line to f
larisa [96]

Answer: Total cost is $1.75

Explanation:

Since we have given that

Number of postcards bought by Doug's family= 7

Cost of each postcard including tax = $0.25

Total cost is given by

7\times 0.25=\$1.75

Now, we want to show this in number line :

On the number line put all the number with a difference of 0.25 and run the number line seven times and we get the answer.

Each step is of length 0.25 and there are 7 jumps to reach required answer.

So, after 7 jumps we reach at 1.75 which is the required answer.

Hence total cost is $1.75

3 0
3 years ago
Find the value of x for which m||n <br> A:38 B:62 C:103 D:150
Alecsey [184]

Answer:

I think the answer is B= 62  

Step-by-step explanation:

Please mark brainliest and have a great day!

8 0
3 years ago
Find the area of the trapezoid?
Verdich [7]

Answer: 52.5 units squared

Step-by-step explanation:

The formula to find the area of a trapezoid is, (base1 + base2)/2 * height

So you find out which variable is which

Base 1 = 4

Base 2 = 3

Height = 15

Then plug it into the formula,

(4+3)/2 * 15

Then solve the order of operations

7/2 * 15

3.5 * 15

52.5 is the answer

8 0
3 years ago
Read 2 more answers
Find the area of a circle circumscribing an equilateral triangle of side 15cm.<br> Take pi = 3.14.
miskamm [114]

Answer:

236 cm²

Step-by-step explanation:

Height of an equilateral triangle (h) = √3 /2 (l)

l = side of the equilateral triangle.

h = √3 /2 (15)

In an equilateral triangle the orthocenter, centroid, circumcenter and incenter are in the same spot

The center of the circle is the centroid and height match  with the median. The radius of the circumcircle is equal to two thirds the height.

Formula for the Radius of the circumcircle = 2/3 h

= 2/3 x √3 /2 (15)

= 5 √3 cm     (=radius)

Area of the circle = πr^

= 3.14 x( 5 √3 ) ^

=3.14 x(25*3)

=3.14 x 75

=235.5

=236 cm²

8 0
3 years ago
Fins the zeroes of the quadratic equation : 4√ 5 x^ 2 - 24x - 9√ 5
liubo4ka [24]

Answer:

Step-by-step explanation:

Hello,

First of all, we know that the solution of the following equation

   ax^2+bx+c=0

are

   \dfrac{-b\pm\sqrt{b^2-4ac}}{2a} \ \text{ when } \Delta=b^2-4ac \geq 0

<em>I would suggest that you try to apply this formula first and check the solution only after you try.</em>

Let's apply it in this case, we have:

a=4\sqrt{5} \\ \\ b=-24 \\ \\ c= -9\sqrt{5}

\Delta=b^2-4ac=24^2+4*9*5=1296 \\ \\ \sqrt{\Delta}=36 \ \text{ and the solutions are } \\ \\ \\ x_1=\dfrac{24-36}{8\sqrt{5}}=\dfrac{-12}{8\sqrt{5}}=\boxed{\dfrac{-3}{2\sqrt{5}}} \\ \\x_2=\dfrac{24+36}{8\sqrt{5}}=\dfrac{60}{8\sqrt{5}}=\boxed{\dfrac{15}{2\sqrt{5}}}

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

5 0
3 years ago
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