8! How many moles are in 73410" molecules of KMO,

How are Epigenetic tags different from genes?

meriva

Quick look: In its modern sense, epigenetics is the term used to describe inheritance by mechanisms other than through the DNA sequence of genes. It can apply to characteristics passed from a cell to its daughter cells in cell division and to traits of a whole organism

6 0

3 years ago

Which of the compounds, kh, nh3, c2h6 and hf are ionic compounds?

Readme [11.4K]

The compound which is ionic is Kh

Kh is ionic because ionic compound is made between a metal and a non metal. K( potassium) is a metal while H (hydrogen) is a non metal. The bond between potassium and hydrogen form ionic bond whereby potassium loses one electron and hydrogen gain one electron to form an ionic compound.

6 0

3 years ago

What other product occurs when ac-222 releases an alpha particle?

irga5000 [103]

There is fr-218

hope this did the job, have a nice rest of your day!!

3 0

3 years ago

A weather balloon is inflated to a volume of 27.9L at a pressure of 732mmHg and a temperature of 30.1?C. The balloon rises in th

masya89 [10]

Answer:

45.4 L

Explanation:

Using Ideal gas equation for same mole of gas as

$\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}$

Given ,

V₁ = 27.9 L

V₂ = ?

P₁ = 732 mmHg

P₂ = 385 mmHg

T₁ = 30.1 ºC

T₂ = -13.6 ºC

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T₁ = (30.1 + 273.15) K = 303.25 K

T₂ = (-13.6 + 273.15) K = 259.55 K

Using above equation as:

$\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}$

$\frac{{732}\times {27.9}}{303.25}=\frac{{385}\times {V_2}}{259.55}$

$\frac{385V_2}{259.55}=\frac{20422.8}{303.25}$

$148225V_2=6729708.26018$

Solving for V₂ , we get:

7 0

3 years ago

El pH de una solución acuosa 10^-14 M de ácido acético, a 25°C, es igual a, teniendo en cuenta que Ke = 1.76x10^-5

frez [133]

Answer:

$pH=14$

Explanation:

Hola!

En este caso, consideramos que la disociación de ácido acético ocurre:

$CH_3COOH\rightarrow CH_3COO^-+H^+$

Así, mediante la solución del equilibrio ácido, podemos calcular la concentración de iones hidronio que posteriormente sirven para calcular el pH de la solución, por tal razón, debemos calcular el equilibrio dada la constante de equilibrio y por medio de la ley de acción de masas en términos del cambio $x$ como cualquier problema de equilibrio:

$Ke=\frac{CH_3COO^-][H^+]}{[CH_3COOH]}\\\\1.76x10^{-5}=\frac{x*x}{1x10^{-14}M-x}$

Resolviendo para $x$ , tenemos $x=0.999x10^{-14}$

Así, la concentración de hidrógeno es igual a x, por lo que el pH:

$pH=-log([H^+])=-log(0.999x10^{-14})\\\\pH=14$

Dicho valor tiene sentido desde que la concentración de hidrógeno es casi despreciable, por lo que se puede asumir que tiende a ser básica.

Saludos!

5 0

3 years ago

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