Answer:
The answer is below
Explanation:
(a) 1s22s22p63s23p5 it's a halogen, halogens are in group 7A in the periodic table, that means that that have 7 electrons in the outermost shell.
outermost shell = 3 number of electrons = 2 + 5 = 7
(b) 1s22s22p63s23p63d74s2 it's an alkaline earth metal, these elements are in the 2A group and have 2 electrons in the outermost shell.
outermost shell 4 number of electrons = 2
(c) 1s22s22p63s23p63d104s24p6 This is an inert gas, these elements have 8 electrons in the outermost shell.
outermost shell 4 number of electrons = 2 + 6 = 8
(d) 1s22s22p63s23p64s1 This is a alkali metal, these elements have 1 electron in the outermost shell
outermost shell 4 number of electrons = 1
(e) 1s22s22p63s23p63d104s24p64d55s2 it's a transition metal. Besides this the outermost shell of this element is 5, shell 4 is incomplete, (4d5) letter d is for transition metal.
outermost shell 5, we consider 4 number of electrons (d) = 5
(f) 1s22s22p63s2 it's an alkaline earth metal, these elements are in the 2A group and have 2 electrons in the outermost shell.
outermost shell 3 number of electrons = 2
