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Karo-lina-s [1.5K]
2 years ago
14

a body of mass 4 kg moves around a circle of radius 6 m with a constant speed of 12m/sec². calculate tw angular velocity and the

force towards the centre​
Physics
1 answer:
NeTakaya2 years ago
3 0

Answer:

• Angular velocity is 2 m/s

• Centripetal force is 96 N

Explanation:

For angular velocity:

{ \rm{v =  \omega r}}

  • v is velocity
  • w is angular velocity
  • r is radius

{ \rm{ \omega =  \frac{v}{r} }} \\  \\ { \rm{ \omega =  \frac{12}{6} }} \\  \\  { \boxed{ \rm{ \omega = 2 \:  {ms}^{ - 1} }}}

For the centripetal force:

{ \rm{force = m { \omega}^{2}r }} \\  \\ { \rm{force = (4 \times  {2}^{2}  \times 6)}} \\  \\ { \rm{force = 96 \: newtons}}

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Triss [41]

Answer:

The sum of positive and negative charges in a unit of Al2O3 equals zero.

Aluminium has a charge of +3 while Oxygen has a charge of -2 on each ion.

Al203 has 2 Al atoms and 3 O atoms.

Charge on Al2O3 = 2(charge on Al ion) + 3(charge on O ion)

= 2(3) + 3(-2)

= 6 - 6

= 0

Explanation:

Aluminium has 3 electrons in the outermost shell and has the tendency to lose those 3 electrons to form a positive ion and have a complete outermost shell.

Whereas, Oxygen has 6 electrons in the outermost and has the tendency to accept two more electrons to form a negative ion and have a complete outermost shell.

4 0
3 years ago
You are watching an object that is moving in shm. when the object is displaced 0.600 m to the right of its equilibrium position,
larisa [96]
It should take at least 4.50

8 0
3 years ago
A small button placed on a horizontal rotating platform with diameter 0.320 m will revolve with the platform when it is brought
Otrada [13]

Answer:

0.2687 approximately 0.27

Explanation:

Diameter = 0.320

Speed = 40.0 rev/min

We are required to find coefficient of static friction between friction and button

The radius can be calculated as

0.320/2

= 0.160m

Then we have the rotational speed w = 40rev/min x 2pi/60

= 4.19 rad/s

umg = mrw²

u = mrw²/mg

u = rw²/g -------(1)

g = 9.8

When we put values into equation 1

0.150m x 4.19² / 9.8

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This is approximately 0.27

6 0
3 years ago
What is the definition of differentiation geology?
UkoKoshka [18]
Any process in which a mixture of materials separates out partially
5 0
4 years ago
Whats the force of gravitation of a 10kg rock and 100kg boulder which are 5 meters apart​
spayn [35]

Answer:

F = 2.6692 x 10⁻⁹ N

Explanation:

Given,

The mass of the rock, m = 10 kg

The mass of the boulder, M = 100 kg

The distance between them, d = 5 m

The gravitational force between the two bodies is proportional to the product of their masses and inversely proportional to the square of the distance between them. It is given by the formula

                                   <em> F = GMm/d²  newton</em>

Where,

                                 G - Universal gravitational constant

Substituting the given values,

                                 F = 6.673 x 10⁻¹¹ x 100 x 10 / 5²

                                 F = 2.6692 X 10⁻⁹ N

Hence, the force between the two bodies is, F = 2.6692 X 10⁻⁹ N

6 0
3 years ago
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