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4 years ago

weather is the day-to-day conditions of an area including A. temperature B. Wind Speed C. humidity D. all of the above

2 answers:

7 0

Hey there!

<span>Weather is the day-to-day conditions of an area including

Answer:
- temperature
- wind speed
- humidity
So your answer is all of the above

Hope this helps! (:
</span>

Natalka [10]4 years ago

6 0

I’d say your answer would be D

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An 8.0 g bullet is fired from a gun at 120 m/s into a 2.0 kg block of wood sitting on a fence post. If the bullet hits the wood

nydimaria [60]

Answer:

$v = 0.478 m/s$

Explanation:

As we know that bullet strike the block and fix in it

so here if bullet and box is taken as a system then there is no external force on it

so here the initial momentum of bullet and block must be equal to final momentum of bullet and block

so here we have

$m_1v_{1i} + m_2v_{2i} = m_1v + m_2v$

now we have

$m_1 = 8 g$

$v_1 = 120 m/s$

$m_2 = 2kg$

$v_{2i} = 0$

now from above equation we have

$(0.008)(120) + 2(0) = (0.008)v + 2v$

$v = 0.478 m/s$

8 0

3 years ago

Which motor and body should Devon use to build the car with the greatest acceleration?

PilotLPTM [1.2K]

<u>Complete Question:</u>

Devon has several toy car bodies and motors. The motors have the same mass, but they provide different amounts of force, as shown in this table.

The bodies have the masses shown in this table (refer attached figure).

Which motor and body should Devon use to build the car with the greatest acceleration?

motor 1, with body 1

motor 1, with body 2

motor 2, with body 1

motor 2, with body 2

<u>Answer:</u>

Devon should build the car with motor 2 and body 1 for having the greatest acceleration.

<u>Explanation:</u>

As per Newton's second law of motion, the acceleration of any object is directly proportional to the force on the object and inversely proportional to the mass of the object.

It can be seen that motor 2 has greater force than the force provided by motor 1. Similarly, the mass of body 1 is found to be lesser compared to mass of body 2. So,

$acceleration =\frac{\text { Force }}{\text { mass }}$

It gives, the system with motor 2 and body 1 the maximum acceleration. So the car should be built with motor 2 and body 1.

5 0

3 years ago

Read 2 more answers

The gravitational force between two objects in space is 800 million

atroni [7]

<h2>Answer:</h2><h3><u>mass and weight </u></h3><h2>Explanation:</h2><h3><u>The Moon is smaller and has less mass than the Earth, so its gravitational field strength is only about one-sixth of the Earth's. So, for example, a 120 kg astronaut weighs 1200 N on Earth but only 200 N on the Moon. </u></h3>

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3 0

3 years ago

A cannonball fired with an initial speed of 40 m/s and a launch angle of 30 degrees from a cliff that is 25m tall.

KATRIN_1 [288]

We know that the ball traveled with an initial velocity of 40m/s at a 30° angle above the horizontal. The image below shows how much of this velocity was upward velocity and how much was horizontal velocity. Upward velocity was 20 m/s and horizontal velocity was √(40) m/s, or 2√(10) m/s. We get these numbers from the ratios of the 30-60-90 triangle.

a) What is the flight time of the cannonball?
The flight time of the cannonball can be found by finding the time at which the upward velocity equals zero (the top of the ball's trajectory) and then finding how long it took to hit the ground after that point.

To find where upward velocity equals zero:
V = Vi - a(t) , where V equals vertical velocity, Vi equals initial vertical velocity, and a equals acceleration due to gravity (-9.8 m/s²)
V = 20 - 9.8(t) Set V equal to zero, because we want to find the moment when the ball reached the peak of its travel path
0 = 20 -9.8t Add 20 to both sides, then divide by 9.8
t = 2.041
This is the point where the ball was at the top of its trajectory.

At this point, How high was the ball?
d = Vi x t + (1/2) (a) (t²) , where d is distance traveled
d = 20(2.041) + (1/2) (-9.8) (2.041²)
d = 20.388
Remember that the ball was launched from 25 m above the ground, so add 25 to the height that the ball traveled from this point:
25 + 20.388 = 45.388
This was the height the ball reached before it started to come down. Plug this into the distance formula to see how long it took to hit the ground. Remember that this is similar to the ball being dropped from rest from this height, since vertical velocity was zero.
45.388 = (0)(t) - (1/2) (-9.8) (t²) Multiply both sides by (-2/-9.8)
9.26 = t²
t = 3.043
We know that it took 2.041 seconds to reach the peak height, and 3.043 seconds to come down.
Total flight time = 2.041 + 3.043 = 5.084 seconds

Remember that, neglecting air resistance, the ball will maintain the same horizontal velocity the entire time. This means the horizontal velocity was 10√2 during the entire flight time.
distance = velocity * time = 5.084 * 10√2 = 32.154

5 0

4 years ago

What are the potential out comes of force

AysviL [449]

Answer:

F in the definition of potential energy is the force exerted by the force field, e.g., gravity, spring force, etc. The potential energy U is equal to the work you must do against that force to move an object from the U=0 reference point to the position r.

Explanation:

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2 years ago