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s2008m [1.1K]
3 years ago
11

Working alone Ryan can dig a 10ft by 10ft hole in five hours castel can dig the same same hole in six how long would it take the

m if they both worked together
Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
3 0

Answer:

The time taken by both when they work together is 2 hours 42 minutes .

Step-by-step explanation:

Given as :

The time taken by Ryan to dig 10 ft by 10 ft hole = x = 5 hours

The time taken bu Castel to dig 10 ft by 10 ft hole = y = 6 hours

Let The time taken by both when they work together = z hours

<u>According to question</u>

The time taken by both when they work together = time taken by Ryan to dig 10 ft by 10 ft hole + time taken bu Castel to dig 10 ft by 10 ft hole

i.e \dfrac{1}{z} = \dfrac{1}{x} + \dfrac{1}{y}

Or,  \dfrac{1}{z} = \dfrac{1}{5}  +  \dfrac{1}{6}

<u>Taking LCM</u>

Or,  \dfrac{1}{z} = \dfrac{6 + 5}{30}

Or,  \dfrac{1}{z} = \dfrac{11}{30}

Or, z = \dfrac{30}{11}   hours

∴  z = 2 hours 42 minutes

So, The time taken by both when they work together = z = 2 hours 42 min

Hence, The time taken by both when they work together is 2 hours 42 minutes . Answer

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