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4 years ago

Do wind up clocks need batteries? -like the non wired ones.

1 answer:

6 0

No, why? Cause if you're winding up the clock it's basically doing what it needs to do. So there's no need for batteries.. I hope my sad sentence make sense :p

You might be interested in

A sample of gas occupies 100.0 mL at standard pressure. What volume will the gas occupy at a pressure of 80.0 mm Hg if the tempe

Bogdan [553]

Answer:

950mL

Explanation:

The following were Data were obtained from the question:

Initial volume (V1) = 100mL

Initial pressure (P1) = stp = 760mmHg

Final pressure (P2) = 80mmHg

Final volume (V2) =..?

The final volume of the gas can be obtained by using the Boyle's law equation as follow:

P1V1 = P2V2

760 x 100 = 80 x V2

Divide both side by 80

V2 = (760 x 100) /80

V2 = 950mL

Therefore, the new volume of the gas is 950mL

8 0

4 years ago

Heart attacks can cause sudden death.<br><br> True <br><br> False

rjkz [21]

Answer:

True

Explanation:

8 0

3 years ago

The equilibrium constant, K, for the following reaction is 2.44×10-2 at 518 K: PCl5(g) PCl3(g) + Cl2(g) An equilibrium mixture o

Volgvan

Answer:

[PCl₅] = 0.5646M

[PCl₃] = 0.1174M

[Cl₂] = 0.1174M

Explanation:

In the reaction:

PCl₅(g) ⇄ PCl₃(g) + Cl₂(g)

K equilibrium is defined as:

The initial moles of each compound when volume is 15.3L are:

PCl₅ = 0.300mol/L×15.3L = 4.59mol

Cl₂ = 8.55x10⁻²mol/L×15.3L = 1.308mol

PCl₃ = 8.55x10⁻²mol/L×15.3L = 1.308mol

At 8.64L, the new concentrations are:

[PCl₅] = 4.59mol / 8.64L = 0.531M

[PCl₃] = 1.308mol / 8.64L = 0.151M

[Cl₂] = 1.308mol / 8.64L = 0.151M

At these conditions, reaction quotient, Q, is:

Q = [0.151M] [0.151M] / [0.531M]

Q = 4.29x10⁻²

As Q > K, <em>the reaction will shift to the left producing more reactant, </em>that means equilibrium concentrations are:

[PCl₅] = 0.531M + X

[PCl₃] = 0.151M - X

[Cl₂] = 0.151M - X

<em>Where X is reaction coordinate.</em>

Replacing in K expression:

2.44x10⁻² = [0.151M - X] [0.151M - X] / [0.531M + X]

1.296x10⁻² + 2.44x10⁻²X = 0.0228 - 0.302X + X²

Solving for X:

X = 0.293 → False solution. Produce negative concentrations

<em>X = 0.0336M → Right solution.</em>

Replacing:

[PCl₅] = 0.531M + 0.0336

[PCl₃] = 0.151M - 0.0336

[Cl₂] = 0.151M - 0.0336

4 0

4 years ago

What is the equilibrium constant, KC if the reaction is a gas phase reaction? (Ans.: Gas: KC = 0.328 dm3/mol)

valentina_108 [34]

Answer:

Equilibrium constant Kc = Qc = quotient of reactant(s) and product(s)

Kc = [C]x[D]y..../[A]m[B]n..... = 0.328dm3/mol, where [C]x[D]y is the product and [A]m[B]n is the reactant(Both in gaseous states)

Explanation:

When a mixture of reactants and products of a reaction reaches equilibrium at a given temperature, its reaction quotient always has the same value. This value is called the equilibrium constant (K) of the reaction at that temperature. As for the reaction quotient, when evaluated in terms of concentrations, it is noted as Kc.

That a reaction quotient always assumes the same value at equilibrium can be expressed as:

Qc (at equilibrium) = Kc =[C]x[D]y…/[A]m[B]n…

This equation is a mathematical statement of the law of mass action: When a reaction has attained equilibrium at a given temperature, the reaction quotient for the reaction always has the same value.

6 0

3 years ago

What is the mass of of 3.20 X 10^23 particles of Co2?

vitfil [10]

Answer:

Mass = 23.36 g

Explanation:

Given data:

Number of particles of CO₂ = 3.20 ×10²³

Mass of CO₂ = ?

Solution:

1 mole contain 6.022×`10²³ particles,

3.20 ×10²³ particles × 1 mol / 6.022×`10²³ particles

0.531 mol

Mass of CO₂:

Mass = number of moles × molar mass

Molar mass = 44 g/mol

Mass = 0.531 mol× 44 g/mol

Mass = 23.36 g

6 0

3 years ago