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belka [17]
3 years ago
5

List three quantum numbers you know

Chemistry
2 answers:
dangina [55]3 years ago
5 0

Answer:

The main quantum numbers are

1) Principal quantum no.

2) Azimuthal quantum no.

3)Magnetic quantum no.

4) Spin quantum no.

Serhud [2]3 years ago
3 0

Answer:principle quantum number

Angular quantum number

Magnetic quantum number

Spin quantum number

Explanation:

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CHEMISTRY MCQ HELP NEEDED, THANKS!
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Thats the answer please mark me as brainiest

7 0
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kogti [31]

Answer:

2812.6 g of H₂SO₄

Explanation:

From the question given above, the following data were obtained:

Mole of H₂SO₄ = 28.7 moles

Mass of H₂SO₄ =?

Next, we shall determine the molar mass of H₂SO₄. This can be obtained as follow:

Molar mass of H₂SO₄ = (1×2) + 32 + (16×4)

= 2 + 32 + 64

= 98 g/mol

Finally, we shall determine the mass of H₂SO₄. This can be obtained as follow:

Mole of H₂SO₄ = 28.7 moles

Molar mass of H₂SO₄ =

Mass of H₂SO₄ =?

Mole = mass / Molar mass

28.7 = Mass of H₂SO₄ / 98

Cross multiply

Mass of H₂SO₄ = 28.7 × 98

Mass of H₂SO₄ = 2812.6 g

Thus, 28.7 mole of H₂SO₄ is equivalent to 2812.6 g of H₂SO₄

3 0
3 years ago
What is dependent on the ability of water molecules to form hydrogen bonds with other molecules besides water
Vikentia [17]

Answer:

The ability of water molecules to form hydrogen bonds with other molecules besides water is the universality of water as a solvent.

Explanation:

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7 0
3 years ago
Complete and balance the molecular equation for the reaction of aqueous sodium carbonate, Na 2 CO 3 Na2CO3 , and aqueous nickel(
antoniya [11.8K]

<u>Answer:</u> The net ionic equation is written below.

<u>Explanation:</u>

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of sodium carbonate and nickel (II) chloride is given as:

Na_2CO_3(aq.)+NiCl_2(aq.)\rightarrow 2NaCl(aq.)+NiCO_3(s)

Ionic form of the above equation follows:

2Na^{+}(aq.)+CO_3^{2-}(aq.)+Ni^{2+}(aq.)+2Cl^{-}(aq.)\rightarrow NiCO_3(s)+2Na^+(aq.)+2Cl^-(aq.)

As, sodium and chloride ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.

The net ionic equation for the above reaction follows:

Ni^{2+}(aq.)+CO_3^{2-}(aq.)\rightarrow NiCO_3(s)

Hence, the net ionic equation is written above.

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Answer:

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Explanation:

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