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Galina-37 [17]
3 years ago
13

Molarity prctice c.10.c

Chemistry
1 answer:
Cerrena [4.2K]3 years ago
3 0

Answer what are you asking

Explanation:

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What is the equations that decompose hydrogen peroxide
Rufina [12.5K]
2H2O2 decomposes into the products 2H2O + O2(g)
5 0
2 years ago
Determine the value of the equilibrium constant, KgoalKgoalK_goal, for the reaction CO2(g)⇌C(s)+O2(g)CO2(g)⇌C(s)+O2(g), Kgoal=?
NISA [10]

Answer:

The value of the equilibrium constant for reaction asked is 1.24\times 10^{-7}.

Explanation:

CO_2(g)\rightleftharpoons C(s)+O_2(g)

K_{goal}=?

K_{goal}=\frac{[C][O_2]}{[CO_2]}

2CO_2(g)+2H_2O(l)\rightleftharpoons CH_3COOH(l)+2O_2(g)..[1]

K_1=\frac{[CH_3COOH][O_2]^2}{[CO_2]^2[H_2O]^2}

2H_2(g)+O2(g)\rightleftharpoons 2H_2O(l)..[2]

K_2=\frac{[H_2O]^2}{[H_2]^2[O_2]}

CH_3COOH(l)\rightleftharpoons 2C(s)+2H_2(g)+O_2(g)..[3]

K_3=\frac{[C]^2[H_2]^2[O_2]}{[CH_3COOH]}

[1] +  [2] + [3]

2CO_2(g)\rightleftharpoons 2C(s)+2O_2(g)

 ( on adding the equilibrium constant will get multiplied with each other)

K=K_1\times K_2\times K_3

K=5.40\times 10^{-16}\times 1.06\times 10^{10}\times 2.68\times 10^{-9}

K=1.53\times 10^{-14}

K=\frac{[C]^2[O_2]^2}{[CO_2]^2}

On comparing the K and K_{goal}:

K^2=K_{goal}

K_{goal}=\sqrt{K}=\sqrt{1.53\times 10^{-14}}=1.24\times 10^{-7}

The value of the equilibrium constant for reaction asked is 1.24\times 10^{-7}.

4 0
3 years ago
A piece of iron is heated with a torch to a temperature of 603 k.
Mazyrski [523]
This question asks to compare the energy emitted by a piece of iron at T = 603K with the energy emitted by the same piece at T = 298K.

Then you need to use the Stefan–Boltzmann Law

That law states that energy emitted (E) is proportional to fourth power of the  to the absolute temperature (T), this is E α T^4 (the sign α is used to express proportionallity.

Then E (603) / E (298) = [603K / 298K]^4 = 16,8

Which meand that the Energy emitted at 603 K is 16,8 times the energy emitted at 298K.


5 0
3 years ago
Which statement is true about a catalyst?
mixas84 [53]

Answer:

Option B: It remains unused during the reaction

Explanation:

Just took the test and got it right.

8 0
3 years ago
Use the periodic table to select which type of bond is present and which of the listed properties is most likely for each substa
Gre4nikov [31]
A-covalent because the two elements are non-metals.
B- ionic because one element is metal (K) and the other element is non-metal(O).
I hope that helps :)
7 0
3 years ago
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