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Naily [24]
2 years ago
9

The equation that represents

Chemistry
1 answer:
dlinn [17]2 years ago
6 0
CH and O is the reactants while CO and H2O is the products
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What is the meaning of<br> 3 CO2 in a chemical reaction?
puteri [66]

Three is simply the coefficient which tells you the amount of molecules. In this case, there are three carbon dioxide molecules. If you want to break it down further, it also means there is three carbon atoms and six oxygen atoms.

I hope this helps.

7 0
2 years ago
Helium, neon, and argon are examples of
iogann1982 [59]
C) Noble gases
The six noble gases are helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), and radon (Rn). Their atomic numbers are, respectively, 2, 10, 18, 36, 54, and 86.
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How is the AHfusion used to calculate the energy required to vaporize a
faust18 [17]
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2 years ago
Write 0.00000009345 in Engineering Notation with 3 significant figures
melisa1 [442]

Answer:

93.43\times 10^{-9}

Explanation:

Scientific notation is the way of writing numbers which are either large or small. The number is written in the scientific notation when the number is between 1 and 10 and then multiplied by the power of 10. Engineering notation is the same version of the scientific notation but the number can be between 1 and 1000 and in this exponent of the ten is divisible by three.

For example, 1000^2 is to be written as 10^6 in engineering notation.

The given number:

0.00000009345 can be written as 93.425\times 10^{-9}

Answer upto 4 significant digits = 93.43\times 10^{-9}

6 0
2 years ago
A scientist digs up sample of arctic ice that is 458,000 years old. He takes it to his lab and finds that it contains 1.675 gram
Fiesta28 [93]

Answer:

6.70 grams of krypton-81 was present when the ice first formed

Explanation:

Let use the below formula to find the amount of sample

N= N_0(\frac{1}{2})^n

where

n = \frac{t}{t_{\frac{1}{2}}}

here

t =  458,000 years

t_{\frac{1}{2}} = 229,000

\frac{t}{t_{\frac{1}{2}}} = \\frac{ 458,000}{229,000}

n = \frac{t}{t_{\frac{1}{2}}} = 2.000

Now substituting the values

1.675 = N_0(\frac{1}{2})^{2.000}}

1.675 = N_0\times (0.2500)

N_0= \frac{1.675}{0.2500}

N_0=6.70

3 0
2 years ago
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