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Alexxandr [17]
3 years ago
10

Use the graph of y =g(x) to graph the given function.

Mathematics
1 answer:
Semenov [28]3 years ago
3 0

Answer:

See image attached

Step-by-step explanation:

This type of transformation corresponds to a reflection of the function's graph around the x axis. Therefore one should obtain the mirror image of the segments on he upper quadrant as shown in red in the attached image.

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For the function f(x)=-3x+2, find f(2)=
dsp73

Answer: f(2) = -4

Step-by-step explanation: Here we're given the function f(x) = -3x + 2 and we are asked to find f(2).

In other words, if we put an <em>x</em> into our function, we get a -3x + 2 out so what happens when we put a 2 into the function?

Well if we put a 2 into the function,

that's f(2) and we get -3(2) + 2 out.

Now all we have to do is simplify on the right side.

-3(2) is -6 so we have -6 + 2 which is -4.

So f(2) is -4.

8 0
3 years ago
Yeah so help please.
irina [24]

Answer:

could you possibly zoom in

Step-by-step explanation:

7 0
3 years ago
anyone know the answer i worked it out but didn't know where i messed up so i am just gonna ask for someone to help me with it.
hram777 [196]
I also worked it out but I got -5/3

2(6p-5) ≥ 3(p-8) -1

12p-10 ≥ 3p-24-1

12p-10 ≥ 3p-25

12p-3p ≥ -25+10

9p ≥ -15

-15/9

P ≥ -5/3
5 0
3 years ago
Help i dont know what to do i give brainlist
Y_Kistochka [10]

Answer:

473 yd^3

Step-by-step explanation:

The surface area of the square base is (11 yd)^2, or 121 yd^2.

The surface area of one of the slanting sides of the pyramid is

A = (1/2)(b)(h), which comes to A = (1/2)(11 yd)(16 yd) = 88 yd^2.

Thus, four such sides have a combined surface area of 352 yd^2.

Combining the surface areas of the slanting sides with the base area yields 473 yd^3

4 0
3 years ago
Which graph shows h(x) = f(x)/g(x)
pogonyaev

Answer:

What is the graph of h(x)=f(x)+g(x) with an example?

So many possible combinations of types of equations for f(x) and g(x).

If they are both linear. f(x) = 3x + 2. g(x) = 2x - 5. h(x) = f(x) + g(x) = 5x - 3. This is also linear.

f(x) has slope = 3 and y-intercept = 2. g(x) has slope = 2 and y intercept = -5. h(x) has slope = 5 and y-intercept = -3.

The graph of the sum of two linear equations is a straight line with slope equal to the sum of the slopes of the two linear equations and a y-intercept equal to the sum of the y-intercepts of the two linear equations.

If one is linear and the other is quadratic. f(x) = 2x + 3. g(x) = x^2 + 6x - 4. h(x) = f(x) + g(x) = x^2 + 8x - 1. This is quadratic.

f(x) has slope = 3 and y-intercept = 3. g(x) has an axis of symmetry of x = -3, vertex at (-3, -13), y-intercept = -4, x-intercepts = -3 + 13^½ and -3 - 13^½ . h(x) has an axis of symmetry of x = -4, vertex at (-4, -17), y-intercept = -1, x-intercepts = -4 + 17^½ and -4 - 17^½ .

The graph of the sum of a linear equation [y = mx + b] and a quadratic equation [y = Ax^2 + Bx + C] has an axis of symmetry of x = - (B + m) / 2A, vertex at ( - (B + m) / 2A, - (B + m)^2 / 4A + (b + C)), y-intercept = b + C, x-intercepts = (- (B + m) + ( (B + m)^2 - 4A (b + C))^½ ) / 2A and (- (B + m) - ( (B + m)^2 - 4A (b + C))^½ ) / 2A .

7 0
3 years ago
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