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Nutka1998 [239]

2 years ago

7

Find the 20th term of the arithmetic sequence 15, 9, 3, -3, ...

1 answer:

RUDIKE [14]2 years ago

4 0

The 20th term is -106

15,9,3,-3,-9,-15,-21,-28,-35,-41,-46 (10) -6 x 10 = -60

-60 + -46

-106

You're just subtracting by 6.

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PLEASE HELP ASAP -- WITH THE WORKK<br><br>50 points

MAXImum [283]

Part-A:-

<h3>(f×g)=</h3>

$\\ \sf\longmapsto x^2+3x-70(4x-12)$

$\\ \sf\longmapsto 4x^2+12x-280-12x^2+36x+840$

$\\ \sf\longmapsto -8x^2+48x+560$

Now

$\\ \sf\longmapsto (f.g)(3)$

$\\ \sf\longmapsto -8(3)^2+48(3)+560$

$\\ \sf\longmapsto -72+144+560$

$\\ \sf\longmapsto 72+560$

$\\ \sf\longmapsto 632$

Part-B:-

$\\ \sf\longmapsto f(3)$

$\\ \sf\longmapsto (3)^2+3(3)-70$

$\\ \sf\longmapsto 9+9-70$

$\\ \sf\longmapsto 18-70$

$\\ \sf\longmapsto -52$

Now

$\\ \sf\longmapsto g(f(3))$

$\\ \sf\longmapsto g(-52)$

$\\ \sf\longmapsto 4(-52-3)$

$\\ \sf\longmapsto 4(-55)$

$\\ \sf\longmapsto -220$

Part:-C

$\\ \sf\longmapsto g(-2)$

$\\ \sf\longmapsto 4(-2-3)$

$\\ \sf\longmapsto 4(-5)$

$\\ \sf\longmapsto -20$

Now

$\\ \sf\longmapsto f(g(-2))$

$\\ \sf\longmapsto f(-20)$

$\\ \sf\longmapsto (-20)^2+3(-20)-70$

$\\ \sf\longmapsto 400-60-70$

$\\ \sf\longmapsto 400-130$

$\\ \sf\longmapsto 270$

Part-D:-

g×f=f×g

$\\ \sf\longmapsto (g.f)(-2)$

$\\ \sf\longmapsto -8(-2)^2+48(-2)+560$

$\\ \sf\longmapsto 32-96+560$

$\\ \sf\longmapsto -64+560$

$\\ \sf\longmapsto 496$

6 0

2 years ago

What's the hcf and lcm of 5and 7

svetlana [45]

Answer:

gcf, hcf, gcd (5; 7) = 1: greatest (highest) common factor (divisor), calculated. Coprime numbers (relatively prime). Numbers have no common prime factors.

7 0

2 years ago

Read 2 more answers

Find the missing side lengths

hichkok12 [17]

Answer:

a = 17

b = 17

Answered by GAUTHMATH

3 0

3 years ago

Read 2 more answers

1) 13 + 3W - 9 + 16w

nevsk [136]

Answer:

4+19W

Step-by-step explanation:

You would just simplify the terms, 13-9=4 and 3W+16W=19W

5 0

2 years ago

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What is the minimum number of students, each of whom comes from one of the 50 states, who must be enrolled in a university to gu

erik [133]

Answer:

4951 students

Step-by-step explanation:

If there was 99 students from each state, that would make the total to be:

99 * 50 = 4950

We can use the pigeon hole principle to make this the minimum number required.

The pigeon hole principle basically tells us that if you have more "pigeons" than "holes" then there must be one hole with multiple objects in it.

So, using this idea, we see that:

we need at least 1 more to ensure this

So, min number required would be

4950 + 1 = 4951

5 0

2 years ago