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mr_godi [17]
3 years ago
7

the volume of a triangular pyramid is 300 cubic meters. what is the area of the pyramid's base of the pyramid height is 3 meters

?
Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
7 0
Volume of a pyramid=area of base×height
∴base area=volume÷height
=300m³÷3m
=100m²
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What is the domain and range of y=x^2?
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<span>On the other hand, a cubic function y=x^3 is quite different from the parabola. For any x that we plug in to the function, we'd always get a value for y, thus there are no restrictions. And the domain is ALL REAL NUMBERS or from -INFINITY to + INFINITY. For the y-values, the case would be quite similar but different to that of the y=x^2. Since a negative number raised to the third power gives us negative values, then the graph would cover positive and negative values for y. Thus, the range is ALL REAL NUMBERS or from -INFINITY to + INFINITY. Good luck!!!:D</span>
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3 years ago
Read 2 more answers
What is 27/54 equivalent to
uranmaximum [27]
27/54 is equivalent to, assuming you want to simplify

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Divide: 83.5 ÷ 6.25 The first step in solving 83.5 ÷ 6.25 is to multiply the divisor and dividend by . The new division problem
kherson [118]

Answer:

The first step in solving 83.5 ÷ 6.25  is to multiply the divisor and dividend by  

[✔ 100 ]

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Step-by-step explanation:

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guapka [62]

Usando la división de términos con la <u>misma base y diferentes exponentes</u>, se encuentra que la expresión simplificada está dada por:

k^{-5}l^{-8}n^6a^{-4} = \frac{n^6}{k^5l^8a^4}

<h3>¿Cómo dividir términos con la misma base y diferentes exponentes?</h3><h3 />

Para hacer la división, mantenemos la base y restamos los exponentes.

En este problema, la división es dada por:

\frac{-k^6l^1n^9}{-k^{11}l^9n^3a^4}

Por lo tanto, el resultado es:

k^{6-11}l^{1-9}n^{9-3}a^{0-4} = k^{-5}l^{-8}n^6a^{-4} = \frac{n^6}{k^5l^8a^4}

Como tanto el numerador como el denominador son negativos, la división es positiva.

Puede-se aprender más a cerca de la división de términos con la <u>misma base y diferentes exponentes</u> en brainly.com/question/15722035

#SPJ1

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