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Ray Of Light [21]
3 years ago
12

PLEASE HELP ME ITS URGENT

Mathematics
2 answers:
uranmaximum [27]3 years ago
4 0

1. A = area of frame; s = length; w = width

2. A = 15^2 - (15 - 2(2))^2 = 225 - 121 = 104

3. A = 18^2 - (18-2(3))^2 = 324 - 144 = 180 --> 180 square inches *20 cents = 3600 cents = $36

Arte-miy333 [17]3 years ago
3 0

Answer:

1) A is area of frame, s is the length of the frame, and w is the width of the frame

2) just plug in the numbers. 15 for s and 2 for w. you get 104

3) the area would be 180 so she would charge $36

Step-by-step explanation:

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A person is chosen at random from a room that contains 24 men and 26 women. What is the probability that a woman is chosen?
Shkiper50 [21]

Answer:

C.13/25

Step-by-step explanation:

There are 50 people in total and 26 out of them are women

if a person chosen randomly from the room the probability of it being a woman is 26/50 whıich we can simplify to 13/25

3 0
3 years ago
Which of the following is an example of an improper fraction? a. 10/3, b.6/7, c. 4/5, d. 3/10
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Answer:

A. 10/3

Step-by-step explanation

improper fraction examples;

\frac{12}{3}   \frac{10}{9}   \frac{11}{10}

An improper fraction is a fraction that has a numerator bigger than the denominator, ( \frac{N}{D} ), therefore the answer would be A.

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7 0
3 years ago
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A hot metal bar is submerged in a large reservoir of water whose temperature is 60°F. The temperature of the bar 20 s after subm
True [87]

Answer:

A) cooling constant =  0.0101365

B) \frac{df}{dt} = k ( 60 - F )

c)  F(t) = 60 + 77.46e^{0.0101365t}

D)137.46 ⁰

Step-by-step explanation:

water temperature = 60⁰F

temperature of Bar after 20 seconds = 120⁰F

temperature of Bar after 60 seconds = 100⁰F

A) Determine the cooling constant K

The newton's law of cooling is given as

= \frac{df}{dt} = k(60 - F)

= ∫ \frac{df}{dt} = ∫ k(60 - F)

= ∫ \frac{df}{60 - F} = ∫ kdt

= In (60 -F) = -kt - c

       60 - F = e^{-kt-c}

      60 - F = C_{1} e^{-kt}       ( note : e^{-c} is a constant )

after 20 seconds

C_{1}e^{-k(20)} = 60 - 120 = -60  

therefore C_{1} = \frac{-60}{e^{-20k} } ------- equation 1

after 60 seconds

C_{1} e^{-k(60)} = 60 - 100 = - 40  

therefore C_{1} = \frac{-40}{e^{-60k} } -------- equation 2

solve equation 1 and equation 2 simultaneously

= \frac{-60}{e^{-20k} } = \frac{-40}{e^{-60k} }

= 6e^{20k} = 4e^{60k}

= \frac{6}{4} e^{40k} = In(6/4) = 40k

cooling constant (k) = In(6/4) / 40 = 0.40546 / 40 = 0.0101365

B) what is the differential equation  satisfied

substituting the value of k into the newtons law of cooling)

60 - F = C_{1} e^{0.0101365(t)}  

F(t) = 60 - C_{1} e^{0.0101365(t)}

The differential equation that the temperature F(t) of the bar

\frac{df}{dt} = k ( 60 - F )

C) The formula for F(t)

t = 20 , F = 120

F(t ) = 60 - C_{1} e^{0.0101365(t)}

120 = 60 - C_{1} e^{0.0101365(t)}

C_{1} e^{0.0101365(20)} = 60

C_{1} = 60 * 1.291 = 77.46

C1 = - 77.46⁰ as the temperature is decreasing

The formula for f(t)

= F(t) = 60 + 77.46e^{0.0101365t}

D) Temperature of the bar at the moment it is submerged

F(0) = 60 + 77.46e^{0.01013659(0)}

F(0) = 60 + 77.46(1)

     = 137.46⁰

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4 years ago
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