X=width of a coccer pitch
2x-20=length of a soccer pitch
Area (rectangule)=length x width
We suggest this equation:
x(2x-20)=6000
2x²-20x=6000
2x²-20x-6000=0
x²-10x-3000=0
We solve this quadratic equation:
x=[10⁺₋√(100-4*1*-3000)]/2=[10⁺₋√(100+12000)]/2=
=(10⁺₋110)/2
we have two solutions:
x₁=(10-110)/2=-50, invalid solution.
x₂=(10+110)/2=60
x=60
2x-20=2(60)-20=120-20=100
Solution: the length is 100 m, and the width is 60 m.
To check:
Area=100 m*60 m=6000 m²
The twice of width is =2(60 m)=120 m,
20 m less than twice its width is: 120 m-20 m=100 m=the length.
Answer:
240
Step-by-step explanation:
In this proble, we are asked to determine the roots of the quadratic equation x^2 + 11 x = -24. The standard form is x^2 + 11 x + 24 = 0. the second term is the negative sum of the roots and the third terms is the equal to the product of the roots.Hence the roots should be -3 and -8.
Answer:
See explanation
Step-by-step explanation:
The average rainfall when you add all 10 years of rainfall up and divide by 10 is an average of 59.946 inches of rain each year. The equation for the data is y = -0.53x + 64.45, this means that the rainfall is getting less each year at a -0.53 inches of rain each year.
x = year (2004 would be 4, etc)
Your answer is 550000!!!
Hope this helped!!!XD
Also can I get brainiest?XD
