The average rate of change (AROC) of a function f(x) on an interval [a, b] is equal to the slope of the secant line to the graph of f(x) that passes through (a, f(a)) and (b, f(b)), a.k.a. the difference quotient given by
![f_{\mathrm{AROC}[a,b]} = \dfrac{f(b)-f(a)}{b-a}](https://tex.z-dn.net/?f=f_%7B%5Cmathrm%7BAROC%7D%5Ba%2Cb%5D%7D%20%3D%20%5Cdfrac%7Bf%28b%29-f%28a%29%7D%7Bb-a%7D)
So for f(x) = x² on [1, 5], the AROC of f is
![f_{\mathrm{AROC}[1,5]} = \dfrac{5^2-1^2}{5-1} = \dfrac{24}4 = \boxed{6}](https://tex.z-dn.net/?f=f_%7B%5Cmathrm%7BAROC%7D%5B1%2C5%5D%7D%20%3D%20%5Cdfrac%7B5%5E2-1%5E2%7D%7B5-1%7D%20%3D%20%5Cdfrac%7B24%7D4%20%3D%20%5Cboxed%7B6%7D)
Answer:
180 degrees
Step-by-step explanation:
Answer:
5. no
6. all
7. all
Step-by-step explanation:
Answer:
7a + b - 16c
Step-by-step explanation:
So we have
7a-3b+c-8c+4b-9c
When it comes to problem like these, you need to combine like terms.
There's only one 'a' number, so that one remains the same.
Next, we have -3b and 4b. (-3b+4b)= b
Finally, there's (c-8c-9c).
(-8c-9c)= -17c
Take that and add the positive 'c' to it.
(-17c+c)= -16c
Put it all together now to get:
7a + b - 16c
I hope that helped and helped you understand at least a little
:)
Answer:
1/3 is answer.
I hope you got it. I had added solved answer too.
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