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Igoryamba
4 years ago
15

Find the missing leg of a right triangle if one leg is 5 and the hypotenuse is 13

Mathematics
2 answers:
Solnce55 [7]4 years ago
7 0

Answer:

a^2 = 13^2-5^2 which is 144

then square root it and its 12

Step-by-step explanation:

Softa [21]4 years ago
6 0
Use Pythagorean theorem (a squared is equal to c squared minus b squared)

Where a is the unknown leg, c is the hypotenuse and b is the known leg

a^2 = 13^2-5^2 which is 144

Then square root one hundred and fourty four to get rid of the power on a

Square root of one hundred and fourty four is twelve
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Find the approximate length of segment AC. Math item stem image CLEAR CHECK 5.74 units 8.06 units 11 units 65 units
laiz [17]

Answer:

         \large\boxed{\large\boxed{8.06units}}

Explanation:

The figure is a right triangle with:

  • hypotenuse = segment AC
  • vertical leg = 7 units
  • horizontal leg = 4 units

Hence, you must use Pythagora's theorem, which is valid for all right triangles:

             hypotenuse^2=(leg_1)^2+(leg_2)^2

Substituting the data:

        hypotenuse^2=(7unit)^2+(4unit)^2=49unit^2+16unit^2=65unit^2

Square root both sides:

         hypotenuse=\sqrt{65unit^2}=8.06unit

8 0
3 years ago
Which of these are unit ratesA square yard for every 100 grass seeds4 acres for 800 plants2 plants in a square foot6 plants in 1
tiny-mole [99]

2 plants in a square foot

6 plants in a square yard

8 seeds per square foot

8 0
3 years ago
Given the function f(x)=x^2+2x+1, find a f(−7)
tatuchka [14]

Answer:

36

Step-by-step explanation:

f(x)=x^2+2x+1

Let x = -7

f(-7)=(-7)^2+2*-7+1

     = 49 -14+1

     = 36

3 0
3 years ago
there are 60 teams attend a chess tournament. every team will play with every other team exactly once. Supposed each team has a
Karolina [17]

The probability that no two teams win the same number of games, P ≈ 2.084 × 10⁻⁴⁵³

The reason for arriving at the above probability is as follows:

The given parameters are;

The number of teams in the tournament, n = 60

The chance of a team winning a game = 50% = 0.5

The number of ties = No ties

The required parameter:

The probability that no two teams win the same number of games

Method:

Calculate the number of ways no two teams win the same number of games, and divide the result by the total number of possible outcomes

Solution:

The number of matches played, n = \dbinom {60} {2} = 1,770

The possible outcomes = 2; Winning or losing

The total number of possible outcomes, n_p = 2¹⁷⁷⁰

The number of games won by each team is between 0 and 59

The ways in which no two teams won the same number of games is given by the games won by the teams to be 0, 1, 2,..., 57, 58, 59

Therefore, the number of ways no two teams won the same number of games, the required outcomes, n_k = 59!

Probability = \dfrac{Number \ of \ possible \ outcomes}{Number \ of \ required\ outcomes}

The probability that no two teams win the same number of games is given as follows;

\mathbf{P(No \ two \ teams \ won \ the \ same \ number \ of \ games)} = \dfrac{n_k}{n_p}

Therefore;

P(No \ two \ teams \ won \ the \ same \ number \ of \ games) = \dfrac{59!}{2^{1,770}} \approx \mathbf{2.084 \times 10^{-453}}

The probability that no two teams win the same number of games, P ≈ 2.084 × 10⁻⁴⁵³

Learn more about probability theory here:

brainly.com/question/1539712

3 0
3 years ago
Help please!! -1/y^-4
Step2247 [10]

Answer:Move

y

−

4

to the numerator using the negative exponent rule

1

b

−

n

=

b

n

.

−

y

4

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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