We know that
the distance from the centroid of the triangle to one of the vertices is the radius of the circle <span>required to inscribe an equilateral triangle.
[distance </span>centroid of the triangle to one of the vertices]=(2/3)*h
h=the <span>altitude of the equilateral triangle-----> 5.196 in
so
</span>[distance centroid of the triangle to one of the vertices]=(2/3)*5.196
[distance centroid of the triangle to one of the vertices]=3.464 in----> 3.5 in
the radius is equal to the distance of the centroid of the triangle to one of the vertices
hence
the radius is 3.5 in
the answer is
the radius is 3.5 in
Answer:
1/8
Step-by-step explanation:
I'm going to try to explain this as easy as possible. What I did was take the original shape and divide it by the new shape. For this question, I solved it by dividing 32(the original base) by 4(the new base) and got 8. So the scale factor of the reduction was 1/8.
I am confident that the best option is Last one in this case.
Answer:
2 1/3
Step-by-step explanation:
If you would like to know what is f(2), you can
calculate this using the following steps:<span>
f(0) = 2
f(n+1) = - 2 * f(n) + 3
f(1) = - 2 * f(0) + 3 = - 2 * 2 + 3 = - 4 + 3 =
- 1
f(2) = - 2 * f(1) + 3 = - 2 * (-1) + 3 = 2 + 3 =
5
The correct result would be f(2) = 5.</span>
