Answer:
Option D is correct = -273 °C
Explanation:
Data given:
Temperature of absolute zero
Absolute Zero in Celsius = ?
Solution:
As we know
internationally the temperature of Absolute zero on kelvin scale = 0 K
So to convert Kelvin temperature to degree Celsius formula will used
T(K) = T(°C) + 273
Rearrange the above equation for °C
T(°C) = T(K) - 273 . . . . (1)
Put value in above eq.1
T(°C) = 0 - 273
T(°C) = -273
So,
The absolute zero in °C = -273
so option D is correct
1.0153 x 10^3
essentially, scientific notation requires you to take a very large or very small number and simplify it into the first few digits times 10 raised to the power of x.
Although realistically, there is no practical reason to simplify a number that is already that close to 1.
Explanation:
Sodium has atomic number of 11 and its electronic configuration is given by:
![[Na]=1s^22s^22p^63s^1](https://tex.z-dn.net/?f=%5BNa%5D%3D1s%5E22s%5E22p%5E63s%5E1)
The nearest stable electronic configuration to sodium is of the neon. So, in order to attain stability of noble gas it will loose its single electron.
![[Na^+]=1s^22s^22p^63s^0](https://tex.z-dn.net/?f=%5BNa%5E%2B%5D%3D1s%5E22s%5E22p%5E63s%5E0)
Sodium has single valency that is 1.
Let nbe the valency of the ion 'X'
By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.
So, the formulas for all the possible compounds that sodium can form with the other ions will be:
An increased number of rod cells
Answer:
By decreasing the volume, the equilibrium will shift to the side with the smallest amount of particles
Explanation:
Step 1: Data given
The principle of Le Chatelier says:
When the volume is decreased, the equilibrium will shift to the side of the smallest number of particles.
2NOBr(g) ⇌ 2NO(g)+Br2(g)
In the following example, we have 2 moles of NOBr (on the left side) and 3 moles of gas on the right side. This means the left side, the reactant side, has the smallest number of particles.
The equilibrium will here shift to the left side, the side of NOBr.
In the following example
2NO2(g) ⇌ N2O4(g)
We have 2moles of NO2 on the left side and 1 mol of N2O4 on the right side.
By decreasing the volume, the equilibrium will shift to the side of the smallest number of moles. Here this is the right side, the side of N2O4.
