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3 years ago

Please answer each:) <3

1 answer:

Nutka1998 [239]3 years ago

4 0

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↪1) Aqueous Solution

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The pH of 0.50 M benzoic acid is 2.24. Calculate the change in pH when 2.64 g of C6H5COONa is added to 38 mL of 0.50 M benzoic a

meriva

Answer:

1.93

Explanation:

Moles of C $_{6}$ H $_{5}$ COOH = 38/1000 × 0.50 = 0.019mol

Moles of C $_{6}$ H $_{5}$ COONa = Mass/Molar mass = 2.64/144.10 = 0.018321mol

Final pH = pKa + log([C $_{6}$ H $_{5}$ COONa]/[C $_{6}$ H $_{5}$ COOH]

= -log Ka + log(mols of C $_{6}$ H $_{5}$ COONa]/mols of C $_{6}$ H $_{5}$ COOH

= -log(6.5 × 10^(-5)) + log (0.018321/0.019)=4.17

change in pH = final - initial pH

= 4.17 - 2.24

=1.93

5 0

4 years ago

If the length, width, and height of a box are 10.00 cm, 7.25 cm and 3.00 cm, respectively, what is the volume of the box in unit

Blizzard [7]

Answer:

For a: The volume of the box is 217.5 mL

For b: The volume of the box is 0.2175 L

Explanation:

The box is a type of cuboid.

To calculate the volume of cuboid, we use the equation:

$V=lbh$

where,

V = volume of cuboid

l = length of cuboid = 10.00 cm

b = breadth of cuboid = 7.25 cm

h = height of cuboid = 3.00 cm

Putting values in above equation, we get:

$V=10.00\times 7.25\times 3.00=217.5cm^3$

For a:

To convert the volume of cuboid into milliliters, we use the conversion factor:

$1mL=1cm^3$

So,

$\Rightarrow 217.5cm^3\times (\frac{1mL}{1cm^3})\\\\\Rightarrow 217.5mL$

Hence, the volume of the box is 217.5 mL

For b:

To convert the volume of cuboid into liters, we use the conversion factor:

$1L=1000cm^3$

So,

$\Rightarrow 217.5cm^3\times (\frac{1L}{1000cm^3})\\\\\Rightarrow 0.2175L$

Hence, the volume of the box is 0.2175 L

3 0

4 years ago

Determine how many grams of precipitate (solid) will form when 621 g of magnesium

kakasveta [241]

Answer:

2,981g

Explanation:

Firstly, we need to find the number of moles of MgCl that we have by using the formula: mass = No. Moles x Molar Mass, which we can rearrange so that we are solving for no. moles:

No. Moles = mass / Molar Mass

We are given a mass of 621g, and we can calculate the molar mass of MgCl by adding the two molar masses together: 24.31+35.45 = 59.76

Now we can calculate number of moles by substituting these values into the formula:

n = 621 / 59.76

No. moles = 10.4

Now we can use the co-efficients in the formula to tell us how many moles of AgCl will be formed. The coefficient of MgCl is 1, and the coefficient of AgCl is 2. This means that every 1 mol of MgCl will form 2 moles of AgCl. So, to find the no. moles of AgCl, we multiply our no. moles by 2:

10.4 x 2 = 20.8 moles

Finally we convert this back into mass by multiplying the no. moles by the Molar mass of AgCl:

m = 20.8 x (107.87+35.45)

m = 2,981g

8 0

3 years ago

HALPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP!!!!!!!!!!!!!!!

Vilka [71]

Answer:

in position and time graphs the slope of line indicates the velocity

3 0

3 years ago

Explain how using dimensional analysis could have prevented this crash

emmainna [20.7K]

Dimensional analysis is a convenient technique to determine if the solution you're following would lead you to the answer that you're looking for. It is the manipulation of units. Like units are cancelled whenever they appear on the numerator and the denominator side. For example, if the speed is 5 m/s and the time is 2 s, the distance would be:

(m/s)*(s) = m

So, you would know that the solution would be 5*2 because it yields the unit for distance.

Hence, dimensional analysis could prevent crash by calculating the right velocities or distances of the two vessels to prevent collision.

4 0

4 years ago