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sukhopar [10]
3 years ago
8

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Chemistry
1 answer:
hram777 [196]3 years ago
5 0

Answer:no question is written

Explanation:

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Calculate the number of grams of sodium chloride in the solution. (Hint: Remember that sodium chloride is a strong electrolyte.)
creativ13 [48]

The question is incomplete, here is the complete question:

A solution contains 0.115 mol  H_2O and an unknown number of moles of sodium chloride. The vapor pressure of the solution at  30°C  is 25.7 torr. The vapor pressure of pure water at this temperature is 31.8 torr. Calculate the number of grams of sodium chloride in the solution. (Hint: Remember that sodium chloride is a strong electrolyte.)

<u>Answer:</u> The mass of sodium chloride in the solution is 0.714 grams

<u>Explanation:</u>

The formula for relative lowering of vapor pressure will be:

\frac{p^o-p_s}{p^o}=i\times \chi_{\text{solute}}

where,  

p^o = vapor pressure of solvent (water) = 31.8 torr

p^s = vapor pressure of the solution = 25.7 torr

i = Van't Hoff factor = 2

\chi_{\text{solute}} = mole fraction of solute (sodium chloride) = ?

Putting values in above equation, we get:

\frac{31.8-25.7}{31.8}=2\times \chi_{NaCl}\\\\\chi_{NaCl}=0.0959

Mole fraction of a substance is calculated by using the equation:

\chi_A=\frac{n_A}{n_A+n_B}

\chi_{\text{NaCl}}=\frac{n_{\text{NaCl}}}{n_{\text{NaCl}}+n_{\text{water}}}

We are given:

Moles of water = 0.115 moles

0.0959=\frac{n_{\text{NaCl}}}{n_{\text{NaCl}}+0.115}\\\\n_{\text{NaCl}}=0.0122mol

To calculate the mass for given number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Moles of NaCl = 0.0122 moles

Molar mass of NaCl = 58.5 g/mol

Putting values in above equation, we get:

0.0122mol=\frac{\text{Mass of NaCl}}{58.5g/mol}\\\\\text{Mass of NaCl}(0.0122mol\times 58.5g/mol)=0.714g

Hence, the mass of sodium chloride in the solution is 0.714 grams

5 0
3 years ago
A 250 ml sample of saturated a g o h solution was titrated with h c l , and the endpoint was reached after 2. 60 ml of 0. 0136 m
nata0808 [166]

A 250 ml sample of saturated a g o h solution was titrated with h c l , and the endpoint was reached after 2. 60 ml of 0. 0136 m h c l was dispensed. Based on this titration, what is the k s p of a g o h <u>. Ksp=1.9×10⁻⁸</u>

<h3>What is titration?</h3>

Titration is a typical laboratory technique for quantitative chemical analysis used to calculate the concentration of a specified analyte. It is also referred to as titrimetry and volumetric analysis (a substance to be analyzed). A standard solution with a known concentration and volume is prepared as the reagent, also known as the titrant or titrator. To ascertain the concentration of the analyte, the titrant reacts with an analyte solution (also known as the titrand). The titration volume is the amount of titrant that interacted with the analyte.

A typical titration starts with a beaker or Erlenmeyer flask being placed below a calibrated burette or chemical pipetting syringe that contains the titrant and a little amount of the indicator (such as phenolphthalein).

To learn more about titration from the given link:

brainly.com/question/186765

#SPJ4

5 0
1 year ago
What is kinetic energy? *
finlep [7]

Answer:

energy which a body possesses by virtue of being in motion

Explanation:

the work needed ro accelerate a body of given mass

4 0
2 years ago
Which of the following statements about the combustion of glucose with oxygen to form water and carbon dioxide (C6H12O6 + 6 O2 →
worty [1.4K]

Answer:

The correct statement is:

E - The entropy of the products is greater than the entropy of the reactants.

Explanation:

C₆H₁₂O₆ + 6 O₂ → 6 CO₂ + 6 H₂O

As glucose is a large molecule and then it is transformed into many molecules of water and carbon dioxide, the entropy of the system increases. If the number of molecules increases, the disorder increases.

Initial state: 7 molecules (1 glucose + 6 oxygen)

Final state: 12 molecules (6 carbon dioxide + 6 water)

3 0
3 years ago
Read 2 more answers
I am running a reaction that creates 138 grams of sulfur trioxide (S03). My theoretical yield was 156 grams. What is my percenta
alex41 [277]

Answer:

88.46%

Explanation:

Percentage yield is actual/theoretical * 100

138/156 * 100 = 88.4615385

5 0
3 years ago
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