No idea.. I think if you take angle (<) MNL then divide those...
Answer : The final pressure of the basketball is, 0.990 atm
Explanation :
Gay-Lussac's Law : It is defined as the pressure of the gas is directly proportional to the temperature of the gas at constant volume and number of moles.

or,

where,
= initial pressure = 1.10 atm
= final pressure = ?
= initial temperature = 
= initial temperature = 
Now put all the given values in the above equation, we get:


Thus, the final pressure of the basketball is, 0.990 atm
B- is the answer
Hope this helps
Have a nice day~
Answer is: a) I only.
Above critical temperature of CO₂, a gas cannot be liquefied no matter how much pressure is applied. Temperature and pressure above its critical point is called supercritical fluid and this is <span>intermediate between gaseous and liquid states.</span>
Hello!
Find the Energy of the Photon by Planck's Equation, given:
E (photon energy) =? (in Joule)
h (Planck's constant) = 
f (radiation frequency) =
Therefore, we have:





I Hope this helps, greetings ... DexteR! =)