Take 68.2/60 = 1.137 hr
take 56.9/1.137 = 50.043 mi/hr
take 189/211 = 0.896
24.8/2 = 12.4 m
12.4/82.3 = 0.15s
Answer:

Explanation:
We are given that







We have to find the exit temperature.
By steady energy flow equation



Substitute the values




Explanation:
1. Force applied on an object is given by :
F = W = mg
(a) A 160 lb human being, F = 160 lb
g = acceleration due to gravity, g = 32 ft/s²


m = 5 kg
(b) A 1.9 lb cockatoo, F = 1.9 lb


m = 0.059 kg
2. (a) A 2300 kg rhinoceros, m = 2300 kg

(b) A 22 g song sparrow, m = 22 g = 0.022 kg

Hence, this is the required solution.