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mafiozo [28]
4 years ago
11

The compressed-air tank ab has a 250-mm outside diameter and an 8-mm wall thickness. it is fitted with a collar by which a 40-kn

force p is applied at b in the horizontal direction. knowing that the gage pressure inside the tank is 5 mpa, determine the maximum normal stress and the maximum shearing stress at point k.
Physics
1 answer:
valentinak56 [21]4 years ago
3 0
<span>Assume: neglect of the collar dimensions. Ď_h=(P*r)/t=(5*125)/8=78.125 MPa ,Ď_a=Ď_h/2=39 MPa Ď„=(S*Q)/(I*b)=(40*〖10〗^3*Ď€(〖0.125〗^2-〖0.117〗^2 )*121*〖10〗^(-3))/(Ď€/2 (〖0.125〗^4-〖0.117〗^4 )*8*〖10〗^(-3) )=41.277 MPa @ Point K: Ď_z=(+M*c)/I=(40*0.6*121*〖10〗^(-3))/(8.914*〖10〗^(-5) )=32.6 MPa Using Mohr Circle: Ď_max=(Ď_h+Ď_a)/2+âš(Ď„^2+((Ď_h-Ď_a)/2)^2 ) Ď_max=104.2 MPa, Ď„_max=45.62 MPa</span>
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Using coulomb law

F = \dfrac {kq_{1}q_{2}}{r^{2}}

F = \dfrac{9\times10^{9}\times (46\times1.6\times10^{-19})^{2}C^{2}}{2\times(5.90\times10^{-15})^{2}\ m^{2}}

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3 years ago
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Bas_tet [7]

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3 years ago
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MAXImum [283]

Answer:

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5 0
3 years ago
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7 0
3 years ago
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