Given that,
bug speed, v= 0.85 m/s
time, t =42 s
Final position of bug on meter stick was 27 cm
Starting position of bug on meter stick = ?
Since we know that,
s = vt
s= 0.85*42 = 35.7 cm
this is the distance covered by bug in the given time and velocity.
since the bug is moving in negative direction, starting point will be:
27.0 cm+ 35.7 cm = 62.7 cm
The bugs starting position on meter stick was 62.7 cm.
Answer:2 ft/s
Explanation:
Given
Length of Pole is 9 ft
Length of Joe is 3 ft
Joe walks away from Pole at the rate 4 ft/s
Let Joe is x m away from Pole so its shadow length is x'
From Similar triangle concept

3x'=x+x'
x=2x'
and it is given 
Differentiating



Answer:
x = 45 MPH
Explanation:
given,
Average speed of the first half = 75 MPH
Average speed of entire ride = 60 MPH
Average speed of the second half = ?
let the average speed of the second half = x MPH
now,
average of entire ride is given as 60 mph so,


75 + x = 120
x = 120 -75
x = 45 MPH
hence, the average speed of the second half comes out to be 45 MPH.
Answer:
B. v = λ X f
<em><u>Hope this helps! </u></em>
The correct answer is A) <span>The two magnetic fields repel each other, causing the train to levitate, or hover, above the rails.
In fact, same magnetic poles repel each other, while opposite magnetic poles attract each other. the magnets on bottom of the train and on top of the railway have the same polarities, so they repel each other and this allows the train to levitate.
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